$x-\ registration\ fee\\
y-\ monthly\ fee\\\\
 \left \{ {{x+4y=370} \atop {x+6y=530\ \ |*(-1)}} \right. \\\\
 \left \{ {{x+4y=370} \atop {-x-6y=-530}} \right. \\+-----\\Addition\\\\
-2y=-160\ \ | divide\ by\ -2\\
y=80\\\\
x=370-4y=370-4*80=370-320=50\\\\
Registration\ fee\ is\ equal\ to\ 50\$\ and\ monthly\ fee\ is\ equal\ to\ 80\$.
$

8 0

3 years ago

Given the quadratic equation ax²-5b+4a=0, where a and b are constants has two real an equal roots,find a:b

sergiy2304 [10]

Answer:

Therefore either a:b = 5:4 or a:b=-5:4

Step-by-step explanation:

ax²-5bx+4a=0

Since the quadratic equation has two real root.

Then b²-4ac>0

Here a= a , b= -5b and c=4a

∴(-5b)²-4.a.4a=0

⇔25b²=16a²

⇔5b=±4a

$\Leftrightarrow \frac{a}{b} =\pm\frac{5}{4}$

Therefore either a:b = 5:4 or a:b=-5:4

5 0

4 years ago

Question In picture above

Irina18 [472]

SAS B is the answer!

8 0

3 years ago

Read 2 more answers

Jose purchased 5.5 feet of rope to hang a planter on the back porch.The planter required a set of 3 ropes measuring 18 inches ea

Soloha48 [4]

You have to multiply 18 by three which is 54 inches.
then you have to divide 54 by 12 because a foot is 12 inches.
when you do that you should get 4.5
then you subtract 4.5 by 5.5 and get 1 foot of rope left
18*3=54
54/12=4.5
5.5-4.5=1.0
1 foot of rope

3 0

4 years ago