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UNO [17]
3 years ago
8

pentru a asorta pernele cu sfoara, aura coase fiecareia , pe margini pamblica albastra. cati cm sunt necesari ? rezolva intrun s

ingur ex
Mathematics
1 answer:
lara [203]3 years ago
6 0
I think the answer is  98352 cm.
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If there is 15,000 gallons of water in your basement, how long will it take the 2,500 gph
Alex Ar [27]

Answer:

6 hours

Step-by-step explanation:

well we have 15000 gallons, divided by 2500 since its gallons per hour. we have 6 hours

have a good day

4 0
3 years ago
Read 2 more answers
A rocket is fired with an initial vertical velocity of 40 m/s from a launch pad 45 m high, and its height is given by the formul
N76 [4]

Answer:

1) 125 meters

2) For 9 seconds.

Step-by-step explanation:

The rocket's height is given by the formula -5t^2+40t+45.

Notice that this is a quadratic.

Part 1)

Since this is a quadratic, the highest height the rocket goes will be the vertex of our quadratic. Remember that the vertex of a quadratic in standard form is:

(-\frac{b}{2a}, f(-\frac{b}{2a}))

So, let's identify our coefficients. The standard quadratic form is:

ax^2+bx+c

Therefore, in this case, our a is -5, b is 40, and c is 45.

So, let's find the x-coordinate of our vertex. Substitute 40 for b and -5 for a. This yields:

x=\frac{-(40)}{2(-5)}

Multiply and reduce. So:

x=-40/-10=4

Now, substitute 4 for t to find the height. So:

-5(4)^2+40(4)+45

Evaluate:

=-5(16)+40(4)+45

Multiply and add:

=-80+160+45=125\text{ meters}

Therefore, the highest the rocket goes up is 125 meters.

Part 2)

To find out for how much time the rocket is in the air, we can think about after how many seconds after launch will the rocket land.

If the rocket lands, the height h will be 0. So, we can set our expression equal to 0 and solve for t:

-5t^2+40t+45=0

First, let's divide everything by -5. This yields:

t^2-8t-9=0

We can factor:

(t+1)(t-9)=0

Zero Product Property:

t+1=0\text{ or } t-9=0

Solve for t:

t=-1\text{ or } t=9

In this case, since t is our time in seconds, -1 seconds does not make sense. So, we can remove -1 from our solution set.

Therefore, 9 seconds after launch, the rocket will touch the ground.

Therefore, the rocket was in the air for 9 seconds.

And we're done!

6 0
4 years ago
-0.03x^2+1.53x=0 <br><br> how would i go about solving for x?
inna [77]

Answer:

x = 0, 51

Step-by-step explanation:

<u>→First, you need to factor out the GCF (Greatest Common Factor), which is -0.03x, like so:</u>

-0.03x (x - 51) = 0

<u>→Remove the -0.03 by divide it by both sides:</u>

x(x - 51) = 0

<u>→Separate each, like so:</u>

x = 0

x - 51 = 0

<u>→Solve for x:</u>

x - 51 = 0

x = 51

<u>Your solutions are, 0 and 51.</u>

7 0
3 years ago
The test scores for a math class are shown below.
Nady [450]

Answer:

c. 4.7

Step-by-step explanation:

first, you find the mean of data set:

83 + 85 + 82 + 93 + 83 + 84 + 95 + 87 + 86 + 94 = 872/10 = 87.2

then, you take each number and subtract the mean and square it:

(87.2 - 83)² = (4.2)² = 17.64

(87.2 - 85)² = (2.2)² = 4.84

(87.2 - 82)² = (5.2)² = 27.04

(93 - 87.2)² = (5.8)² = 33.64

(87.2 - 83)² = (4.2)² = 17.64

(87.2 - 84)² = (3.2)² = 10.24

(95 - 87.2)² = (7.8)² = 60.84

(87.2 - 87)² = (0.2)² = 0.04

(87.2 - 86)² = (1.2)² = 1.44

(94 - 87.2)² = (6.8)² = 46.24

now, find the mean of the squared numbers:

17.64 + 4.84 + 27.04 + 33.64 + 17.64 + 10.24 + 60.84 + 0.04 + 1.44 + 46.24 = 219.6/10 = 21.96

then, take the square root of the number you just got:

√21.96 = 4.68

and last but not least, round to the nearest tenth: 4.7

6 0
3 years ago
.) Find the sum of the first n terms of the geometric sequence for the values of a1and r.
Vinvika [58]
Sn = a(r^n - 1)/(r - 1)
S4 = 228(4.8^4 - 1)/(4.8 - 1) = 228(530.8416 - 1)/3.8 = 228(529.8416)/3.8 = 120,803.8848 / 3.8 = 31,790.496
3 0
4 years ago
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