You leave at 1 P.M., the wedding ceremony starts at 5 P.M.
This gives you a 4 hour gap, the Wedding is 350 miles away, and you're traveling at 65 miles an hour.
Simply you can use two methods, (65 * 4) to verify if you'd make it or not or (350/65) to ensure how many hours it would take in total.
65 * 4 = 260 | Since this is not 350, we can verify that you'd be late.
350/65 = 5.4 (estimated) | Meaning it'd take about 5.4 hours.
To know how long that is we'd have to convert over.
5.4 = 5 2/5ths, 60 minutes are in an hour. Divide 60 by 5 to get 12, meaning:
1/5ths = 12/60ths, with that said multiply that by 2 to get your answer.
2/5ths = 24/60ths or 24 minutes.
This means you'd take 5 hours and 24 minutes to get there.
Originally we stated that the process would take 4 hours. Subtract:
(5 hours and 24 minutes) - (4 hours) = (1 hour and 24 minutes)
Concluding that you'd be late by an hour and 24 minutes.
I hope this helps, have a great rest of your day! ^ ^
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Multiply 9.6 pounds of trail mix by $1.20.
9.6 * 1.20 = 11.52
Corrine will spend $11.52 on trail mix.
Answer:
A) Akash (1.5m), Meera (1.52), Rahul (1.54m), Lakshmi (1.56m)
B) Lakshmi is the tallest, 1.56m tall
Step-by-step explanation:
Rahul- 1.54m
Akash- 1500mm
Meera- 152cm
Lakshmi- 1560mm
Let's start by converting all the measurements to meters.
Rahul is already in meters, so he can just stay the same.
1500mm = 1.5m
152cm = 1.52m
1560mm = 1.56m
So our new measurements are:
Rahul- 1.54m
Akash- 1.5m
Meera= 1.52m
Lakshmi= 1.56m
We can now make our conclusions.
A) Akash (1.5m), Meera (1.52), Rahul (1.54m), Lakshmi (1.56m)
B) Lakshmi is the tallest, 1.56m tall
An aritmetic sequence is like this
where a1=first term and d=common difference
geometric is
where a1=first term and r=common ratio
can it be both aritmetic and geometric
hmm, that means that the starting terms should be the same
therfor we need to solve
what values of d and r make all natural numbers of n true?
are there values that make all natural numbers for n true?
when n=1, then d(1-1)=0 and r^(1-1)=1, so already they are not equal
the answer is no, a sequence cannot be both aritmetic and geometric
Answer:
33%
Step-by-step explanation:
Prob(heads) = 1/2
Prob(either red or blue) = 2/3
So Prob( heads and red/blue) = 1/2 * 2/3
= 2/6
= 1/3 which is 33%.
