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pashok25 [27]
3 years ago
14

What is -0.009 to the second power

Mathematics
1 answer:
kondaur [170]3 years ago
5 0
I believe it's -0.000081
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Number 5 all letters anyone? due tomorrow at 8 am
Yuri [45]

Answer:

d.1060

e.140

f.340

g.230

hope it helps

Pls give brainliest

6 0
3 years ago
The constant in the expression 8x 3 + 4x 2 – 9 is
Ket [755]

Answer : 9

Step-by-step explanation:

The answer is 9 because a constant is a number on its own, or sometimes a letter such as a, b or c to stand for a fixed number.

6 0
3 years ago
Do even numbers have more factors in odd numbers or do i numbers have more factors than even numbers
Serggg [28]
<span>It is because even numbers always have a factor of two, and therefore, larger composite even numbers will have factors of two and other even numbers based around two, such as 4, 8, 16, 32, and so on. On the other hand, numbers which are odd can have factors of 3, 5, and 7 for example, and their numbers based around them(3, 9, 27; 5, 10, 15; 7, 49, 343; and so on). If we look into it, notice how for odd numbers the space between the numbers based around 3, 5, and 7 are increasingly further apart. This is the reason why less large odd integers to have numerous factors. It is because odd numbers cannot have the prime factor 2, this will reduce their factor number. And is is also because even numbers are already divided by 2, this will give them more factors over the odd numbers.</span>
4 0
3 years ago
Which expressions are equivalent to the equation below
Irina18 [472]

Answer:

Polynomial Expression.

Step-by-step explanation:

8 0
3 years ago
WILL GIVE BRAINLST <br><br> HAVE A GOOD DAY
Sedbober [7]
1st one 17/100 2nd one 0.25


Because 0.17 would be like 17% out of 100% so the fraction simplified is 17/100

2. Since the area of a square is length×length
But according to the question we are asked to find the length and the area is given so we will have to solve this
L×L= area
L^2=0.25
Square root both sides
L=√0.25
L=0.5
Therefore the length of the square is 0.5
6 0
3 years ago
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