Answer:
SAS
Step-by-step explanation:
II side (given)
Angles between the congruent sides (vertically opposite angle)
III side (given)
Hence by, SAS the Triangles are congruent.
The piecewise function all the way to the left (x + 3) should have an ending point shaded in. [At x = -2] The next function ((x^2) -1) should have both ending points left unshaded. Finally, the logarithm function should have a shaded in starting point [At x = 1] and should have an unshaded ending point at x = 3.
Answer:
a. 64, 128, 256 (geometric)
b. 11, 13, 15 (arithmetic)
c. 53, 61, 69 (arithmetic)
Step-by-step explanation:
(a) Each term is twice the previous term. so it is geometric with a common ratio of 2
(b) The difference between each term is 2. So it is arithmetic with a common difference of 2
(c) The difference between each term is 8. So it is arithmetic with a common difference of 8
Answer: A) Justification 1
<u>Step-by-step explanation:</u>
The student did not match the angles correctly.
∠ABC = 90° and ∠BCD = 60° so they cannot state that the angles are congruent. The other statement on that line is wrong also, but is irrelevant since there is already an error in that line.
Answer:
As e is point between df. So we can write df as
df = de + ef
As given df = 78 , de = 5x - 9 , ef = 2x + 10.
So we can write
78 = 5x - 9 + 2x + 10
78 = 7x + 1
On subtracting 1 on booth side
78 - 1 = 7x +1 - 1
77 = 7x
On dividing both side by 7.
11 = x
So x = 11.
So ef = 2x + 10 = 2*11 + 10 = 22 + 10 = 32
Step-by-step explanation: