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irga5000 [103]
4 years ago
7

GEOMETRY PLZ HELP

Mathematics
1 answer:
Cerrena [4.2K]4 years ago
3 0

Answer:

Option B is true

Step-by-step explanation:

We are given that three right  triangles .Triangles ABD,CAD and CBA are similar.

When two triangles are similar then, the corresponding sidea are in equal proportion.

We have AB=5 units

AC= 7 units

BC=x

Triangles ABD is similar triangle CBA

\frac{AB}{BD}=\frac{BC}{AB}

AB^2=BC\cdot BD

(5)^2=BC\cdot BD

BC\cdot BD=25

When triangle CAD and CBA are similar

Then,\frac{AC}{BC}=\frac{CD}{AC}

AC^2=CD\cdot BC

(7)^2=CD\cdot BC

49=CD\cdot BC

In traingle CBA, uisng pythagoras theorem

AB^2+AC^2=BC^2

BC\cdot BD+BC\cdot CD=x^2

25+49=x^2

x^2=74

Hence, option B is true.

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Can Somebody Help With Geometry?
Cerrena [4.2K]

Answer:

SAS

Step-by-step explanation:

II side (given)

Angles between the congruent sides (vertically opposite angle)

III side (given)

Hence by, SAS the Triangles are congruent.

7 0
3 years ago
Please help I’ll give brainliest
damaskus [11]
The piecewise function all the way to the left (x + 3) should have an ending point shaded in. [At x = -2] The next function ((x^2) -1) should have both ending points left unshaded. Finally, the logarithm function should have a shaded in starting point [At x = 1] and should have an unshaded ending point at x = 3.
6 0
3 years ago
Please help I’ll mark you as brainliest if correct!
Dmitry [639]

Answer:

a. 64, 128, 256  (geometric)

b. 11, 13, 15 (arithmetic)

c. 53, 61, 69 (arithmetic)

Step-by-step explanation:

(a) Each term is twice the previous term. so it is geometric with a common ratio of 2

(b) The difference between each term is 2. So it is arithmetic with a common difference of 2

(c) The difference between each term is 8. So it is arithmetic with a common difference of 8

6 0
1 year ago
Look at the right triangle ABC​
LenaWriter [7]

Answer: A) Justification 1

<u>Step-by-step explanation:</u>

The student did not match the angles correctly.

∠ABC = 90° and ∠BCD = 60° so they cannot state that the angles are congruent. The other statement on that line is wrong also, but is irrelevant since there is already an error in that line.

6 0
3 years ago
DF=78, DE=5x-9, and EF-2x+10, find EF
lbvjy [14]

Answer:

As e is point between df. So we can write df as

df = de + ef

As given df = 78 , de = 5x - 9 , ef = 2x + 10.

So we can write

78 = 5x - 9 + 2x + 10

78 = 7x + 1

On subtracting 1 on booth side

78 - 1 = 7x +1 - 1

77 = 7x

On dividing both side by 7.

11 = x

So x = 11.

So ef = 2x + 10 = 2*11 + 10 = 22 + 10 = 32

Step-by-step explanation:

8 0
3 years ago
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