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SCORPION-xisa [38]
4 years ago
5

Can 8\15 Be simplified

Mathematics
2 answers:
kykrilka [37]4 years ago
5 0
No it cannot be simplified they have no common factors
Fynjy0 [20]4 years ago
3 0
No, 8/15 cannot be simplified, maybe if was 9/15 then it can be 3/5 as 9 and 15 are both divisble by 3
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A beverage is made by mixing 1 part of water with 3 parts of fruit juice. How many parts of water are mixed with 1 part of fruit
forsale [732]

Answer:

1/3

Step-by-step explanation:

for every 1 part of water there is 3 parts juice so if there's only 1 part juice it would be a 1/3

5 0
3 years ago
Read 2 more answers
It takes james 2.5 minutes to type 150 words at that rate how mant words can james type in 6 minutes
sergey [27]

The number of words james can type in 6 minutes at the same rate is 360 words

Given:

Number of minutes to type 150 words = 2.5 minutes

let

number of words James can type in 6 minutes = x

Equate the ratio of the number of words to number of minutes

150 : 2.5 = x : 6

150/2.5 = x/6

cross product

150 × 6 = 2.5 × x

900 = 2.5x

x = 900/2.5

x = 360 words

Therefore, the number of words james can type in 6 minutes is 360 words

Learn more about ratio:

brainly.com/question/16981404

5 0
3 years ago
Read 2 more answers
Jasmine has 3 3 /8 pounds of turkey meat. She is making 1/3 pound turkey burgers. Does Jasmine have enough meat to make 12 turke
Masteriza [31]

Answer: no

Step-by-step explanation:

She needs a little less than 4 pounds to make 12 turkey burgers because 1/3 times 12 is about 3.99 pounds. But she only has 3 3/8 pounds which is about 3.375 pounds.

4 0
4 years ago
Read 2 more answers
A deck of ordinary cards is shuffled and 13 cards are dealt. What is the probability that the last card dealt is an ace?
alexandr1967 [171]

Answer:

The probability that the last card dealt is an ace is \frac{1}{13}.

Step-by-step explanation:

Given : A deck of ordinary cards is shuffled and 13 cards are dealt.

To find : What is the probability that the last card dealt is an ace?

Solution :

There are total 52 cards.

The total arrangement of cards is 52!.

There is 4 ace cards in total.

Arrangement for containing ace as the 13th card is 4\times 51!.

The probability that the last card dealt is an ace is

P=\frac{4\times 51!}{52!}

P=\frac{4\times 51!}{52\times 51!}

P=\frac{4}{52}

P=\frac{1}{13}

Therefore, the probability that the last card dealt is an ace is \frac{1}{13}.

4 0
3 years ago
PLEASE HELP!!!!!!!!!!!!!!!!!
Lelechka [254]

x=4.75

6×4.75=28.5

15×4.75-12=59.25

19×4.75+2=92.25

28.5+59.25+92.25=180

m<MNI= 92.25

I think this is right. I hope that it was helpful:)

8 0
3 years ago
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