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Oxana [17]
3 years ago
6

What is the product?

Mathematics
1 answer:
pashok25 [27]3 years ago
6 0
(-3s +2t)(4s -t) = -12s^2 +3st +8st -2t^2 = -12s^2 +11st -2t^2 so the last one choice is right sure 
You might be interested in
15
alexandr1967 [171]

By using parallel lines and transversal lines concept we can prove m∠1=m∠5.

Given that, a║b and both the lines are intersected by transversal t.

We need to prove that m∠1=m∠5.

<h3>What is a transversal?</h3>

In geometry, a transversal is a line that passes through two lines in the same plane at two distinct points.

m∠1+m∠3= 180° (Linear Pair Theorem)

m∠5+m∠6=180° (Linear Pair Theorem)

m∠1+m∠3=m∠5+m∠6

m∠3=m∠6

m∠1=m∠5 (Subtraction Property of Equality)

Hence, proved. By using parallel lines and transversal lines concept we can prove m∠1=m∠5.

To learn more about parallel lines visit:

brainly.com/question/16701300

#SPJ1

7 0
2 years ago
Where to place the lines
vazorg [7]
Use photo math it works well
7 0
3 years ago
The volume of a spherical sculpture is 256 ft³. Rhianna wants to estimate the surface area of the sculpture. To do the estimate,
Brrunno [24]

Answer:

192 ft^2

Step-by-step explanation:

Given that

Volume of spherical sculpture = 256 ft³

\pi is used as 3.

To find:

Surface area of sculpture = ?

Solution:

First of all, let us learn about the formula for Volume and Surface Area of Sphere:

1. Volume =\frac{4}{3}\pi r^3

2. Surface\ Area = 4\pi r^2

Given volume is 256 ft³.

256 = \dfrac{4}{3}\pi r^3\\\Rightarrow 256 = \dfrac{4}{3}\times 3 r^3\\\Rightarrow 256 = 4 r^3\\\Rightarrow r^3=64\\\Rightarrow \bold{r = 4\ ft}

Now, let us put r = 4 in the formula of Surface Area to find the value of Surface Area:

Surface\ Area = 4\pi 4^2 = 4 \times 3 \times 16 = \bold{192\ ft^2}

So, approximate surface area of sculpture is 192 ft^2.

3 0
3 years ago
Describe the steps you would use to factor 2x3 + 5x2 – 8x – 20 completely. Then state the factored form.
WARRIOR [948]
The polynomial 2x^3 + 5x^2-8x-20 may have solutions which are the divisors of -20, therefore -20 has the following divisors: \pm 1, \pm 2, \pm 4, \pm 5, \pm 10, \pm 20.
If x=1, then 2\cdot1^3 + 5\cdot1^2-8\cdot1-20=-20\neq 0,
if x=-1, then 2\cdot(-1)^3 + 5\cdot(-1)^2-8\cdot(-1)-20=-9\neq 0,
if x=2, then 2\cdot2^3 + 5\cdot2^2-8\cdot2-20=0, then x=2 is a solution and you have the first factor (x-2). 
If x=-2, then 2\cdot(-2)^3 + 5\cdot(-2)^2-8\cdot(-2)-20=0, then x=-2 is a solution, so you have the second factor (x+2).
Since x-2 and x+2 are two factors of 2x^3 + 5x^2-8x-20 , then the polynomial x^2-4 is a divisor of 2x^3 + 5x^2-8x-20 and dividing the polynomial 2x^3 + 5x^2-8x-20 by x^2-4 you obtain 
 2x^3 + 5x^2-8x-20=(x-2)(x+2)(2x+5).











5 0
3 years ago
Read 2 more answers
(Asap please!!! help!!)
lara31 [8.8K]
Are you saying 32 is the total perimeter?

5 0
3 years ago
Read 2 more answers
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