Simplified (4x3 - 5x2 + 3x) + (-2x3 - x2 + 6x)

Mathematics

1 answer:

bogdanovich [222]3 years ago

6 0

Answer:

Answer is imaginary roots

Step-by-step explanation:

$({4x}^{3} - {5x}^{2} + 3x) + ( - {2x}^{3} - {x}^{2} + 6x) \\ 2 {x}^{3} - 6 {x}^{2} + 9x = 0 \\ dividing \: by \: x \\ 2 {x}^{2} - 6x + 9 = 0 \\ dividin g\: by \: 2 \\ {x}^{2} - 3x + \frac{9}{2} = 0 \\ shifting \: the \: constant \: term \: on \: right \: side \\ {x}^{2} - 3x = - \frac{9}{2} \\ adding \: \frac{1}{2} \times (coefficient \: of \: x) \: whole \: square \\$

On solving the above mentioned equation we get some imaginary values.

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