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grin007 [14]
3 years ago
11

What are the coordinates for this point? Point D

Mathematics
2 answers:
TEA [102]3 years ago
4 0
(0,-4) is the coordinate for point D
spayn [35]3 years ago
3 0

Answer:

(-4, 0)

Step-by-step explanation:

We just need to identify where it is on both the x and y axis!

X Axis - Horizontal middle line.

Y Axis - Vertical middle line.

On the x-axis, you can see it is at -4, therefore we know our x is that.

On the y-axis, you can see it hasn't gone up or down from the vertex, showing us that it has neither gone up or down, so it is 0!

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Omar has a gift card for $25 at a clothing store. He wants to buy socks that cost $4 per pair. He also has a coupon for $5 off h
vaieri [72.5K]

Answer:

4x ≤ 30

Step-by-step explanation:

Omar gets 30 dollars off because $25 + $5 = 30. Let x = pairs of socks

We know each pair costs $4, so the cost would be 4x. Omar has to buy as many pairs as he can with only the coupon and gift card. Omar has to spend $30 (the full discount) or less than $30. Therefore, the inequality would be: 4x ≤ 30 or 4x is less than or equal to 30 ($30).

6 0
3 years ago
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Points E, F, and D are located on circle C. Circle C is shown. Line segments E C and D F are radii. Lines are drawn from points
elena55 [62]

Answer:

Option (1). 34°

Step-by-step explanation:

From the figure attached, CE and CD are the radii of the circle C.

Central angle CED formed by the intercepted arc DE = 68°

Since measure of an arc = central angle formed by the intercepted arc

Therefore, m∠CED = 68°

Since m∠EFD = \frac{1}{2}(m\angle ECD) [Central angle of an intercepted arc measure  the double of the inscribed angle by the same arc]

Therefore, m∠EFD = \frac{1}{2}(68)

                               = 34°

Therefore, Option (1) 34° will be the answer.

7 0
3 years ago
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Futhe Mathematics<br><img src="https://tex.z-dn.net/?f=%28Cos%20%7B%7D%5E%7B4%7Dt%20-Sin%20%7B%7D%5E%7B4%7Dt%20%29%20%20%5Cdiv%2
Nastasia [14]

Answer:

cos2t/cos²t

Step-by-step explanation:

Here the given trigonometric expression to us is ,

\longrightarrow \dfrac{cos^4t - sin^4t }{cos^2t }

We can write the numerator as ,

\longrightarrow \dfrac{ (cos^2t)^2-(sin^2t)^2}{cos^2t }

Recall the identity ,

\longrightarrow (a-b)(a+b)=a^2-b^2

Using this we have ,

\longrightarrow \dfrac{(cos^2t + sin^2t)(cos^2t-sin^2t)}{cos^2t}

Again , as we know that ,

\longrightarrow sin^2\phi + cos^2\phi = 1

Therefore we can rewrite it as ,

\longrightarrow \dfrac{1(cos^2t - sin^2t)}{cos^2t}

Again using the first identity mentioned above ,

\longrightarrow \underline{\underline{\dfrac{(cost + sint )(cost - sint)}{cos^2t}}}

Or else we can also write it using ,

\longrightarrow cos2\phi = cos^2\phi - sin^2\phi

Therefore ,

\longrightarrow \underline{\underline{\dfrac{cos2t}{cos^2t}}}

And we are done !

\rule{200}{4}

Additional info :-

<em>D</em><em>e</em><em>r</em><em>i</em><em>v</em><em>a</em><em>t</em><em>i</em><em>o</em><em>n</em><em> </em><em>o</em><em>f</em><em> </em><em>c</em><em>o</em><em>s</em><em>²</em><em>x</em><em> </em><em>-</em><em> </em><em>s</em><em>i</em><em>n</em><em>²</em><em>x</em><em> </em><em>=</em><em> </em><em>c</em><em>o</em><em>s</em><em>2</em><em>x</em><em> </em><em>:</em><em>-</em>

We can rewrite cos 2x as ,

\longrightarrow cos(x + x )

As we know that ,

\longrightarrow cos(y + z )= cosy.cosz -  siny.sinz

So that ,

\longrightarrow cos(x+x) = cos(x).cos(x) - sin(x)sin(x)

On simplifying,

\longrightarrow cos(x+x) = cos^2x - sin^2x

Hence,

\longrightarrow\underline{\underline{cos (2x) = cos^2x - sin^2x }}

\rule{200}{4}

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What is the equation of the line in slope-intercept form?
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Y= Mx+b

In the equation of a straight line,the slope is the number "m" that is multiplied on the x, and "b<span>" is the </span>y<span>-intercept (that is, the point where the line crosses the vertical </span>y<span>-axis).</span>
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Late work 4 physics
Oliga [24]

Answer:

Step-by-step explanation:

problem 4

Velocity is +2.0m/s and constant acceleration is -0.5m/s^2

For every second the velocity drop by 0.5 m/s, so after 2 seconds the velocity is  1 m/s.

problem 5

Accelerate from rest to 28m/s means go from 0 to 28m/s so with

a constant acceleration of 5.5 m/s^2 it will take 5.09 second

7 0
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