Is it supposed to be equal to something, maybe "0"? You wouldn't be able to solve this without that.
Volume = (edge)^3
Volume = (3/4)^3
Volume = (27/64) inches^3
Done.
Answer:
in -5y+8x=-18 and 5y+2x=58
x = 4
in -5y+8x=-18 and 5y+2x=58
y = 10
You have to subtract 8 from the left and then 8 from the right. If you do that then you'll have 5x=15.
Then you divide "x" by 5 and 15 by 5.
X=3
Answer:
C. Kalena made a mistake in Step 3. The justification should state: -x²
+ x²
Step-by-step explanation:
Given the function x(x - 1)(x + 1) = x3 - X
To justify kelena proof
We will need to show if the two equations are equal.
Starting from the RHS with function x³-x
First we will factor out the common factor which is 'x' to have;
x(x²-1)
Factorising x²-1 using the difference of two square will give;
x(x+1)(x-1)
Note that for two real number a and b, the expansion of a²-b² using difference vof two square will give;
a²-b² = (a+b)(a-b) hence;
Factorising x²-1 using the difference of two square will give;
x(x+1)(x-1)
Factorising x(x+1) gives x²+x, therefore
x(x+1)(x-1) = (x²+x)(x-1)
(x²+x)(x-1) = x³-x²+x²-x
The function x³-x²+x²-x gotten shows that kelena made a mistake in step 3, the justification should be -x²+x² not -x-x²
