Answer:
19 6j/5
Step-by-step explanation:
Answer: b
Step-by-step explanation:
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<h3>
Answer: -2</h3>
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Explanation:
We use the remainder theorem. This is the idea where if we divide P(x) over (x-k), then the remainder is P(k).
Comparing x+1 to x-k shows that k = -1
It might help to rewrite x+1 as x-(-1) to get it into the form x-k better.
Plug this k value into the function
f(x) = 2x^6 + 3x^5 - 1
f(-1) = 2(-1)^2 + 3(-1)^5 - 1
f(-1) = 2(1) + 3(-1) - 1
f(-1) = 2 - 3 - 1
f(-1) = -1 - 1
f(-1) =-2
The remainder is -2
We can confirm this through synthetic division or polynomial long division.
1. Understand what multi-variable equations are.
Two or more linear equations that are grouped together are called a system. That means that a system of linear equations is when two or more linear equations are being solved at the same time.
[1] For example:
• 8x - 3y = -3
• 5x - 2y = -1
These are two linear equations that you must solve at the same time, meaning you must use both equations to solve both equations.
2. Know that you are trying to figure out the values of the variables, or unknowns.
The answer to the linear equations problem is an ordered pair of numbers that make both of the equations true.
In the case of our example, you are trying to find out what numbers ‘x’ and ‘y’ represent that will make both of the equations true.
• In the case of this example, x = -3 and y = -7. Plug them in. 8(-3) - 3(-7) = -3. This is TRUE. 5(-3) -2(-7) = -1. This is also TRUE.
3. Know what a numerical coefficient is.
The numerical coefficient is simply the number that comes before a variable.[2] You will use these numerical coefficients when using the elimination method. In our example equations, the numerical coefficients are:
• 8 and 3 for the first equation; 5 and 2 for the second equation.
4. Understand the difference between solving with elimination and solving with substitution.
When you use elimination to solve a multivariable linear equation, you get rid of one of the variables you are working with (such as ‘x’) so that you can solve the other variable (‘y’). Once you find ‘y’, you can plug it into the equation and solve for ‘x’ (don’t worry, this will be covered in detail in Method 2).
• Substitution, on the other hand, is where you begin working with only one equation so that you can again solve for one variable. Once you solve one equation, you can plug in your findings to the other equation, effectively making one large equation out of your two smaller ones. Again, don’t worry—this will be covered in detail in Method 3.
5. Understand that there can be linear equations that have three or more variables.
Solving for three variables can actually be done in the same way that equations with two variables are solved. You can use elimination and substitution, they will just take a little longer than solving for two, but are the same process.
Step-by-step explanation:
height= 4b
length = 2 + b
volume = 60in³
or, l ×b × h = 60in³
or, (2+b) × b × 4b = 60in³
or, 4b²(2+b) = 60in³
or, 8b² + 4b³ = 60
or, 2b² + b³ = 15
or, b³ + 2b² -15= 0
b= 1.95
l= 2+1.95=3.95
h= 4×1.95 = 7.8
