p-6p+7=3(2p-3)-4(-10+4p
We move all terms to the left:
p-6p+7-(3(2p-3)-4(-10+4p)=0
We add all the numbers together, and all the variables
p-6p-(3(2p-3)-4(4p-10)+7=0
We add all the numbers together, and all the variables
-5p-(3(2p-3)-4(4p-10)+7=0
<span>The first two cuts can intersect at only 1 pt regardless of where they are placed.
So 4 pieces there.
The last cut can only intersect each other cut a 1 pt, regardless of placement. As long as the intersection is different than the first intersection, then you will have 7 pieces.</span>
Answer:
v= - 2
Step-by-step explanation:
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Answer:
5/6=10/12. 2/4=6/12. 5/12
5/12. 2/4. 5/6
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