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4 years ago

Write the inequality

Mathematics

1 answer:

Naya [18.7K]4 years ago

5 0

23≤x≤400

x∈[23;400] x has to be equal or more than 23 and max 400 so 400or and less than that

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Student annual household income. A. Nominal. B. Ordinal. C. Interval. D. Ratio

Anuta_ua [19.1K]

Answer: B. Ordinal.

Step-by-step explanation:

8 0

3 years ago

Pls help question is in the images

hodyreva [135]

The symbol $\displaystyle{ T_{\ \textless \ -4, 2\ \textgreater \ }(\triangle ABC)$ means that:

we translate ( shift ) the triangle ABC -4 units horizontally and 2 units vertically.

This means that the triangle needs to be shifted 4 units left, and 2 units up.

The only figure which displays such a movement of the triangle (left, up) is the one in the attachment below. That is the answer.

8 0

3 years ago

<img src="https://tex.z-dn.net/?f=5x%20-%2015%20%2B%20130%20%3D%20x%20-%202%20%20" id="TexFormula1" title="5x - 15 + 130 = x - 2

olga nikolaevna [1]

Answer:

x=-117/4

Step-by-step explanation:

5x-15+130=x-2

5x-x+115=-2

4x+115=-2

4x=-2-115

4x=-117

x=-117/4

6 0

3 years ago

A solid aluminum cube has sides each of length l . A second cube of the same material has sides four times the length of the fir

timofeeve [1]

The formula to find the volume of cube

cube = s^3

Therefore volume is equal to I^3

The second cube has 4x the First cube

4 × (I^3) = 4 ×I^3

Total volume of the second cube= 4I^3 cm3

Fact: the density(mass ÷ volume) of aluminium is 2.40g/cm3

Making mass the subject of the formula:

D = M ÷ V
(Times volume to remove deno minator)

Mass = Density × Volume

Mass = 2.40 × 4I ^3

Mass = 8.40I^3

By physics

weight= m × g

where
M = mass
g = acceleration due to gravity (= 9.8)

W = 8.40 I^3 × 9.8

Weight of aluminium = 82.32I^3

3 0

4 years ago

Franchise Business Review stated over 50% of all food franchises earn a profit of less than $50,000 a year. In a sample of 130 c

nydimaria [60]

Answer:

We need a sample size of 564.

Step-by-step explanation:

In a sample with a number n of people surveyed with a probability of a success of $\pi$ , and a confidence level of $1-\alpha$ , we have the following confidence interval of proportions.

$\pi \pm z\sqrt{\frac{\pi(1-\pi)}{n}}$

In which

z is the zscore that has a pvalue of $1 - \frac{\alpha}{2}$ .

For this problem, we have that:

$\pi = \frac{81}{130} = 0.6231$

The margin of error is:

$M = z\sqrt{\frac{\pi(1-\pi)}{n}}$

95% confidence level

So $\alpha = 0.05$ , z is the value of Z that has a pvalue of $1 - \frac{0.05}{2} = 0.975$ , so $Z = 1.96$ .

Based upon a 95% confidence interval with a desired margin of error of .04, determine a sample size for restaurants that earn less than $50,000 last year.

We need a sample size of n

n is found when $M = 0.04$