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EleoNora [17]
3 years ago
14

A solid aluminum cube has sides each of length l . A second cube of the same material has sides four times the length of the fir

st cube, i.E., 4 l . What is the weight of the second cube
Mathematics
1 answer:
timofeeve [1]3 years ago
3 0
The formula to find the volume of cube

cube = s^3

Therefore volume is equal to I^3

The second cube has 4x the First cube

4 × (I^3) = 4 ×I^3

Total volume of the second cube= 4I^3 cm3

Fact: the density(mass ÷ volume) of aluminium is 2.40g/cm3

Making mass the subject of the formula:

D = M ÷ V
(Times volume to remove deno minator)

Mass = Density × Volume

Mass = 2.40 × 4I ^3

Mass = 8.40I^3

By physics

weight= m × g

where
M = mass
g = acceleration due to gravity (= 9.8)

W = 8.40 I^3 × 9.8

Weight of aluminium = 82.32I^3
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3 years ago
Use chain rule to find dw/dt w=ln(x^2 + y^2 + z^2)^(1/2) , x=sint, y=cost, z=tant
son4ous [18]
The chain rule states that

\dfrac{\mathrm dw}{\mathrm dt}=\dfrac{\partial w}{\partial x}\dfrac{\mathrm dx}{\mathrm dt}+\dfrac{\partial w}{\partial y}\dfrac{\mathrm dy}{\mathrm dt}+\dfrac{\partial w}{\partial z}\dfrac{\mathrm dz}{\mathrm dt}

Since \ln(x^2+y^2+z^2)^{1/2}=\dfrac12\ln(x^2+y^2+z^2), you have

\dfrac{\partial w}{\partial x}=\dfrac x{x^2+y^2+z^2}
\dfrac{\partial w}{\partial x}=\dfrac y{x^2+y^2+z^2}
\dfrac{\partial w}{\partial z}=\dfrac z{x^2+y^2+z^2}

and

\dfrac{\mathrm dx}{\mathrm dt}=\cos t
\dfrac{\mathrm dy}{\mathrm dt}=-\sin t
\dfrac{\mathrm dz}{\mathrm dt}=\sec^2t

Also, since x^2+y^2+z^2=\sin^2t+\cos^2t+\tan^2t=1+\tan^2t=\sec^2t, the derivative is

\dfrac{\mathrm dw}{\mathrm dt}=\dfrac{\sin t\cos t}{\sec^2t}-\dfrac{\sin t\cos t}{\sec^2t}+\dfrac{\tan t\sec^2t}{\sec^2t}
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4 0
3 years ago
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Oxana [17]

Greetings! Hope this helps!

Answer:

"Hecto" Is a meaning for 100, So your answer would be A.) Hecotmeter

_________________

A brainliest will help me tons! :D

8 0
3 years ago
20 POINTS , ALSO GIVING BRAINLIEST , PLEASE HURRY !!
liq [111]

Answer:

.5236

Step-by-step explanation:

Formula for sphere volume:

V = \frac{4}{3} \pi r^{3}

substiture 0.5 for r:

\frac{4}{3} \pi 0.5^{3} = .5236

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3 years ago
Ramòn bought a dozen ears of corn for $1.80. What was the cost of each ear of corn?
Vikentia [17]
One dozen= 12

$1.80/12= $0.15 each

Final answer: $0.15
3 0
3 years ago
Read 2 more answers
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