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GarryVolchara [31]
2 years ago
6

• How can you tell that a point on the graph is a maximum, a minimum, or neither?

Mathematics
1 answer:
Eduardwww [97]2 years ago
4 0

Answer:

If it is on the maximum, then the y-value of the point cannot be any higher and  still be on the graph of the function. If it is on the minimum, the the y-value of the point cannot be any lower and still be on the graph of the function. If it isn't either the maximum or the minimum, it is neither.

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A drone is monitoring the atmospheric conditions above a farm field.
Viefleur [7K]

Answer:

y=5 \ \ \ x x_o + 1.9s

Step-by-step explanation:

This situation can be considered as a piecewise function. First, you take xo as the time in which the drone goes upward. Before this time the height of the drone is constant with a value of 5 m. Next, you take into account that during 1.9 s after xo the drone accelerates. Finally, the drone flies again with a constant height of 5.9m. Hence, this function has three parts:

For the first part you have:

y = 5       for x <  xo

For the second part you first calculate vertical speed (which means the slope of the linear function) by using the following kinematic equation:

y=vx\\\\v=\frac{y-y_o}{x}=\frac{5.9m-5.0m}{1.9s}=0.47m/s

Then you have:

y = 0.47x    for xo < x < xo + 1.9s

And for the third part:

y = 5.9    for x > xo  + 1.9s

Summarizing you obtain:

y=5 \ \ \ x x_o + 1.9s

4 0
3 years ago
You put $800 in an account that earns 4% simple interest. Find the total amount in your account after each year for 3 years. (Pl
alexandr402 [8]
To get 4% of 800 you times 800 by 4 and divide it by 100. Once you have that amount you add it to 800 to find the amount you will have in your bank the first year. To get the next year's amount you then get 4% of 832(because after the first year you have more than $800) and then add the 4% to 832, that is the answer for the second year. To find the third year's amount you get 4% of the new amount (last year's total) and add it to last year's total, that is your total for the third year. So the first year will be: (800x4÷100)+800 =32+800 =832 The second year will be: 832+(832x4÷100) =832+33.28 =865.28 The third year will be: (865.28×4÷100)+865.28 =34.61(rounded off)+865.28 =899.89
3 0
3 years ago
Read 2 more answers
What is the factored form of the expression?<br><br> d^2 = 36d + 324
Veseljchak [2.6K]

Answer:

(x-43.45)(x+7.45)=0

Step-by-step explanation:

We have the quadratic equation d^{2}=36d+324  i.e. d^{2}-36d-324=0

As, the roots of the quadratic equation ax^{2}+bx+c=0 are given by x=\frac{-b\pm \sqrt{b^{2}-4ac}}{2a}.

So, from the given equation, we have,

a = 1, b = -36 , c = -324.

Substituting the values in x=\frac{-b\pm \sqrt{b^{2}-4ac}}{2a}, we get,

x=\frac{36\pm \sqrt{(-36)^{2}-4\times 1\times (-324)}}{2\times 1}

i.e. x=\frac{36\pm \sqrt{1296+1296}}{2}

i.e. x=\frac{36\pm \sqrt{2592}}{2}

i.e. x=\frac{36\pm 50.9}{2}

i.e. x=\frac{36+50.9}{2}  and x=\frac{36-50.9}{2}

i.e. x=\frac{86.9}{2}  and x=\frac{-14.9}{2}

i.e. x = 43.45 and x = -7.45

Thus, the roots of the equation are 43.45 and -7.45.

Hence, the factored form of the given expression will be (x-43.45)(x+7.45)=0

3 0
3 years ago
What is the midpoint of QR. Q(2,4) and R(-3,9)
Eduardwww [97]

Answer:

The answer is

( -  \frac{1}{2}  \: , \:  \frac{13}{2})  \\

Step-by-step explanation:

The midpoint M of two endpoints of a line segment can be found by using the formula

M = (  \frac{x1 + x2}{2} , \:  \frac{y1 + y2}{2} )\\

where

(x1 , y1) and (x2 , y2) are the points

From the question the points are

Q(2,4) and R(-3,9)

The midpoint is

M = ( \frac{2 - 3}{2}  \:  , \:  \frac{9 + 4}{2} ) \\

We have the final answer as

( -  \frac{1}{2}  \: , \:  \frac{13}{2})  \\

Hope this helps you

6 0
2 years ago
I need helpppp (10 points )
irga5000 [103]

Answer:  The flagpole is about 22.3 feet tall.

This is roughly the size of a two story building, assuming each floor is 10 feet or so.

Since this height is under 25 ft, this flagpole is in compliance with the regulation.

=====================================================

Work Shown:

The horizontal leg of the triangle is 36 ft. This is the adjacent leg to the reference angle 25 degrees.

The vertical leg of the triangle is x-5.5, and this leg is the opposite side to the reference angle 25 degrees.

Use the tangent rule to connect the opposite and adjacent sides.

Solve for x.

tan(angle) = opposite/adjacent

tan(25) = (x-5.5)/36

36*tan(25) = x-5.5

x-5.5 = 36*tan(25)

x = 36*tan(25)+5.5

x = 22.28707569358

x = 22.3 ft is the approximate height of the flagpole

Make sure your calculator is in degree mode.

The height is not over 25 ft, so this flagpole meets the requirements.

4 0
3 years ago
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