I believe your answer is:
<span>C. Two times r equals the diameter of the circle. Pi is needed for all circle formulas, so you multiply by Pi since you are finding the circumference.
2r = d or, 2 radius = one diameter
</span>π is used in both circle equations:
<span>
2</span>πr (circumference)
πr² (area of circle)
hope this helps
Multiply 1/6 by 1/6 by 1/6 essentially
(1/6)^3
1/216
Answer:
4
Step-by-step explanation:
48 ÷ 12 = 4
hope this helps
I'm assuming there is a + sign between the 5h & the 2.
But you first get:
15h^2-15h+6h-6
Which simplifies to:
15h^2-9h-6
Divide each term by <span>66</span> and simplify.
<span><span><span>|6−4x|</span>=<span><span>4x</span>3</span>+<span>23</span></span><span><span>|6-4x|</span>=<span><span>4x</span>3</span>+<span>23</span></span></span>Remove the absolute value term. This creates a <span>±±</span> on the right side of the equation because <span><span><span>|x|</span>=±x</span><span><span>|x|</span>=±x</span></span>.<span><span>6−4x=±<span><span>4x</span>3</span>+<span>23</span></span><span>6-4x=±<span><span>4x</span>3</span>+<span>23</span></span></span>Set up the positive portion of the <span>±±</span> solution.<span><span>6−4x=<span><span>4x</span>3</span>+<span>23</span></span><span>6-4x=<span><span>4x</span>3</span>+<span>23</span></span></span>Solve the first equation for <span>xx</span>..<span><span>x=1</span><span>x=1</span></span>Set up the negative portion of the <span>±±</span> solution.<span><span>6−4x=−<span>(<span><span>4x</span>3</span>+<span>23</span>)</span></span><span>6-4x=-<span>(<span><span>4x</span>3</span>+<span>23</span>)</span></span></span>Move <span>xx</span> to the right side of the equation by subtracting <span>xx</span> from both sides of the equation.<span><span>−<span><span>8x</span>3</span>=−<span>203</span></span><span>-<span><span>8x</span>3</span>=-<span>203</span></span></span>Multiply the numerator of the first fraction by the denominator of the second fraction. Set this equal to the product of the denominator of the first fraction and the numerator of the second fraction.<span><span><span>(−8x)</span>⋅<span>(3)</span>=<span>(3)</span>⋅<span>(−20)</span></span><span><span>(-8x)</span>⋅<span>(3)</span>=<span>(3)</span>⋅<span>(-20)</span></span></span>Solve the equation for <span>xx</span>..<span><span>x=<span>52</span></span><span>x=<span>52</span></span></span>The solution to the equation includes both the positive and negative portions of the solution.<span>x=1,<span><span>52</span></span></span>