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Wittaler [7]
2 years ago
7

ellum...........................................11..............................................................................

........
Mathematics
1 answer:
Naddika [18.5K]2 years ago
8 0

Answer:

heyyyyy !!!!! whats the question????? ......

Step-by-step explanation:

You might be interested in
Suppose you are given two angles A and B in which angle a is equal to angle b. If the measure of a compliment of angle a is equa
zepelin [54]
5x + 20 = 90 - a = 90 - (3x + 40)
5x + 20 = 90 - 3x - 40 = 50 - 3x
5x + 3x = 50 - 20
8x = 30
x = 30/8 = 15/4

b = 3(15/4) + 40 = 45/4 + 40 = 51.25
The measure of a supplementary angle is 180 - 51.25 = 128.75
 
4 0
3 years ago
What's the probability of pulling two red cards in a row from a deck of cards?​
monitta

Hey there! I'm happy to help!

Let's say that we don't have jokers. In that case, there are 52 cards, and half of them are red (so 26 are red). The probability of pulling a red card once is 1/2 since half the cards are red.

If we pick one out, there are only 51 total cards left and 25 red cards. So, the probability of picking one again would be 25/51.

We multiply the probabilities of these two events to find the probability of them both happening.

1/2×25/51=25/102

The probability of picking two red cards in a row is 25/102 or around 24.5%.

Have a wonderful day! :D

8 0
2 years ago
How to get 3.15 ratio
REY [17]

Answer:

Step 1) Convert the 3.15 percent to a decimal number.

To convert 3.15 percent to a decimal number, you divide 3.15 by 100. In other words, the quotient you get when you divide 3.15% by 100 is the decimal number.

3.15 ÷ 100 = 0.0315

Step 2) Convert the decimal number to a fraction.

To convert the decimal number to a fraction, we make the decimal number the numerator, and 1 the denominator.

0.0315  =  

   

0.0315

   

1

Step 3) Remove the decimal point in the numerator.

To remove the decimal point in the numerator, multiply both the numerator and denominator by 10000.

   

0.0315 × 10000

   

1 × 10000

 =  

   

315

   

10000

Step 4) Simplify the fraction.

The greatest common factor of 315 and 10000 is 5. Therefore, to simplify the fraction, divide the numerator and denominator by 5.

   

315 ÷ 5

   

10000 ÷ 5

 =  

   

63

   

2000

Step 5) Convert the fraction to a ratio.

To convert the fraction to a ratio, replace the fraction divider line with a colon.

   

63

   

2000

 =  63:2000

That was the final step. Below is the answer to 3.15 percent as a ratio.

3.15% = 63:2000

Step-by-step explanation:

6 0
3 years ago
Read 2 more answers
A rectangle has a length of x+7 and a width of 2x-3. If it’s perimeter is 32, what is the value of 3x? A.4/B.12/C.14/D.36/E.42/
Tamiku [17]

Answer:

The correct option is C. 14.

Step-by-step explanation:

First you have that the perimeter of a rectangle = (2·length) + (2·width)

⇒perimeter of a rectangle = [2·( x + 7)] + [2·(2x - 3)]

⇒ 32 = [2·( x + 7)] + [2·(2x - 3)] ⇒ 32 = (2x + 14) + (4x - 6)

⇒ 32 = 6x + 8 ⇒ 32 - 8 = 6x ⇒ 24= 6x ⇒ 24/6 = x ⇒ x = 4. ⇒ 3x= 12.

7 0
2 years ago
The distribution of lifetimes of a particular brand of car tires has a mean of 51,200 miles and a standard deviation of 8,200 mi
Orlov [11]

Answer:

a) 0.277 = 27.7% probability that a randomly selected tyre lasts between 55,000 and 65,000 miles.

b) 0.348 = 34.8% probability that a randomly selected tyre lasts less than 48,000 miles.

c) 0.892 = 89.2% probability that a randomly selected tyre lasts at least 41,000 miles.

d) 0.778 = 77.8% probability that a randomly selected tyre has a lifetime that is within 10,000 miles of the mean

Step-by-step explanation:

Problems of normally distributed distributions are solved using the z-score formula.

In a set with mean \mu and standard deviation \sigma, the zscore of a measure X is given by:

Z = \frac{X - \mu}{\sigma}

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

In this question, we have that:

\mu = 51200, \sigma = 8200

Probabilities:

A) Between 55,000 and 65,000 miles

This is the pvalue of Z when X = 65000 subtracted by the pvalue of Z when X = 55000. So

X = 65000

Z = \frac{X - \mu}{\sigma}

Z = \frac{65000 - 51200}{8200}

Z = 1.68

Z = 1.68 has a pvalue of 0.954

X = 55000

Z = \frac{X - \mu}{\sigma}

Z = \frac{55000 - 51200}{8200}

Z = 0.46

Z = 0.46 has a pvalue of 0.677

0.954 - 0.677 = 0.277

0.277 = 27.7% probability that a randomly selected tyre lasts between 55,000 and 65,000 miles.

B) Less than 48,000 miles

This is the pvalue of Z when X = 48000. So

Z = \frac{X - \mu}{\sigma}

Z = \frac{48000 - 51200}{8200}

Z = -0.39

Z = -0.39 has a pvalue of 0.348

0.348 = 34.8% probability that a randomly selected tyre lasts less than 48,000 miles.

C) At least 41,000 miles

This is 1 subtracted by the pvalue of Z when X = 41,000. So

Z = \frac{X - \mu}{\sigma}

Z = \frac{41000 - 51200}{8200}

Z = -1.24

Z = -1.24 has a pvalue of 0.108

1 - 0.108 = 0.892

0.892 = 89.2% probability that a randomly selected tyre lasts at least 41,000 miles.

D) A lifetime that is within 10,000 miles of the mean

This is the pvalue of Z when X = 51200 + 10000 = 61200 subtracted by the pvalue of Z when X = 51200 - 10000 = 412000. So

X = 61200

Z = \frac{X - \mu}{\sigma}

Z = \frac{61200 - 51200}{8200}

Z = 1.22

Z = 1.22 has a pvalue of 0.889

X = 41200

Z = \frac{X - \mu}{\sigma}

Z = \frac{41200 - 51200}{8200}

Z = -1.22

Z = -1.22 has a pvalue of 0.111

0.889 - 0.111 = 0.778

0.778 = 77.8% probability that a randomly selected tyre has a lifetime that is within 10,000 miles of the mean

4 0
2 years ago
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