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Mekhanik [1.2K]

3 years ago

14

A bag contains four red marbles, two green ones one lavender one two orange marbles how many sets of five marbles include at mos

t one of the yellow ones

1 answer:

defon3 years ago

8 0

I don't understand the question doesn't make any sense to me sorry for wating ur time but I need the points

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Simplify 4z2 + z2 + 6a.

podryga [215]

5z^2 + 6a is the simplified expression

5 0

2 years ago

Use the discriminant to determine the nature of the roots of the following equation.

kvv77 [185]

Discussion

The discriminate is b^2 - 4*a*c

The general equation for a quadratic is ax^2 + bx + c

In this equation's case

a = 1

b= -5

c = - 3

Solve

(-5)^2 - 4*(1)*(-3)

25 - (-12)

25 + 12

37

Note

Since the discriminate is > 0, the roots are real and different. The roots do exist and there are 2 of them.

4 0

2 years ago

the surface area of a square pyramid is 84 square inches. the side length of the base is 6 inches. what is the value of x?

Sladkaya [172]

The formula is(V=B•h)(84•6)

8 0

3 years ago

En una bandeja, hay 375 pasteles. Si quitásemos 59 pasteles de otra bandeja, en ambas habría igual número de pasteles.

ra1l [238]

Answer:

En una bandeja, hay 375 pasteles. Si quitásemos 59 pasteles de otra bandeja, en ambas habría igual número de pasteles.

<h2>En cada bandeja, ¿Cuántos pasteles hay?</h2>

6 0

2 years ago

A 4-lb. force acting in the direction of (vector) 4,-2 moves an object just over 7ft from point (0,4) to (5,-1). Find the work d

Tcecarenko [31]

To solve this problem, we have to find the net displacement and the net force and the multiply the dot product together and get the work done.

The work done on moving the object is 27ft*lbs

<h3>Work done in moving the object from point A to point B</h3>

To find the work done on this object, let's find the net force on the object.

Data;

force = 4lb
direction = 4, -2
displacement = 7ft
direction = (0, 4) to (5,1)

The unit vector of the force is

$\sqrt{4^2 +(-2)^2} =\sqrt{16 + 4} = \sqrt{20}$

$\frac{4}{\sqrt{20} }, \frac{-2}{\sqrt{20} }$

The net force acting on the object is

$F = 4(\frac{4}{\sqrt{20} }, \frac{-2}{\sqrt{20} })\\F= (\frac{16}{\sqrt{20} }, \frac{-8}{\sqrt{20} } )$

The displacement on the object is 7ft through (0,4) to (5, -1)

The unit vector on displacement is

$\sqrt{5^2 + (-1-4)^2} = \sqrt{25+25} = \sqrt{50}$

$\frac{5}{\sqrt{50} }, \frac{-5}{\sqrt{50} }$

The net displacement will be

$7(\frac{5}{\sqrt{50} }, \frac{-5}{\sqrt{50} }) = \frac{35}{\sqrt{50} }, \frac{-35}{50}$

The work done will be F.d

$w = f. d \\$

$w = (\frac{16}{\sqrt{20} }, \frac{-8}{\sqrt{20} } ) * \frac{35}{\sqrt{50} }, \frac{-35}{50}\\w = 17.71+ 8.854\\w = 26.567 = 27ft*lbs$

The work done on moving the object is 27ft*lbs

Learn more on work done on an object here;

brainly.com/question/26152883

#SPJ1

6 0

2 years ago