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3 years ago

I need help with this problem

Mathematics

1 answer:

zmey [24]3 years ago

4 0

Answer:heres what i got

The left side −0

¯4 is greater than the right side−0.¯¯¯¯¯¯6h means that the given statement is always true.

Step-by-step explanation:

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Mashcka [7]

B: exponential; y=3^x-1

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4 years ago

2x+ 20 + 3x +40 =<br> 60 + 5X

umka21 [38]

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3 years ago

How many ways are there for Alice, Bob, Charlie, David and Eve to line up from left to right, such that Charlie is somewhere to

steposvetlana [31]

Answer:

120 ways

Step-by-step explanation:

Alice, Bob, David, Charlie, Eve

David, Alice, Bob, Charlie, Eve

Alice,David, Bob, Charlie, Eve

Charlie, Eve ,Alice,David, Bob,

Charlie, Eve ,Alice, Bob, David,

Charlie, Eve ,David, Alice, Bob,

Alice,Charlie, Eve , Bob, David,

Alice,Charlie, Eve , David, Bob,

Bob,Alice,Charlie, Eve , David, and so .

This is a permutation question as the order of placing Charlie to the left of Eve is important.

So the total number of people n= 5 and the possible order is 4 keeping Charlie left of Eve. Eve cannot have the last position to keep Charlie on the left.

Using the formula of nPr = n!/ (n-r)! we get

5! / (5-4)! = 120 ways in which Charlie can be placed to the left of Eve.

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3 years ago

You and a friend are sharing a 3/8 bag of candy how much do you get equally

-BARSIC- [3]

Answer:

If both of them got the same amount of the bag then they each got 3/16 of the bag

4 0

3 years ago

Construct the confidence interval for the population mean mu. c = 0.90, x = 16.9, s = 9.0, and n = 45. A 90% confidence inte

Georgia [21]

Answer:

The 90% confidence interval for population mean is $14.7 < \mu < 19.1$

Step-by-step explanation:

From the question we are told that

The sample mean is $\= x = 16.9$

The confidence level is $C = 0.90$

The sample size is $n = 45$

The standard deviation

Now given that the confidence level is 0.90 the level of significance is mathematically evaluated as

$\alpha = 1-0.90$

$\alpha = 0.10$

Next we obtain the critical value of $\frac{\alpha }{2}$ from the standardized normal distribution table. The values is $Z_{\frac{\alpha }{2} } = 1.645$

The reason we are obtaining critical values for $\frac{\alpha }{2}$ instead of that of $\alpha$ is because $\alpha$ represents the area under the normal curve where the confidence level 1 - $\alpha$ (90%) did not cover which include both the left and right tail while $\frac{\alpha }{2}$ is just considering the area of one tail which is what we required calculate the margin of error