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Nuetrik [128]
3 years ago
9

Why do u think each letter in a polygon's name can be used only once

Mathematics
1 answer:
adelina 88 [10]3 years ago
4 0
It is not true.

An octagon is a polygon of 8 sides. The letter "o" appears in octagon two times.

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which expression is equivalent to 100 n2 − 1? (10n)2 − (1)2 (10n2)2 − (1)2 (50n)2 − (1)2 (50n2)2 − (1)2
givi [52]
Which expression is equivalent to 100 n2 − 1? (10n)2 − (1)2 (10n2)2 − (1)2 (50n)2 − (1)2 (50n2)2 − (1)2

Regroup:
100n^2-1

=10^2n^2-1
=(10n)^2-1^2

So the correct answer is : 
(10n)^2-1^2

To attempt to factor a polynomial of four or more terms with no common factor, first rewrite it in groups. Each group may possibly be separately factored, and the resulting expression may possibly lend itself to further factorization if a greatest common factor<span> or special form is created.</span>
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17-2(6-4)(7-3)-7
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During a flu epidemic, 44 students out of the 80 who are in Ms Grant’s class were absent. What percent were absent?
wel
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The dimensions of a box that is a rectangular prism are 3 inches, 4 inches, and 6 inches. What is the length of the diagonal fro
Neporo4naja [7]

Answer:

7.8 in

Step-by-step explanation:

Given:-

- The dimension of rectangular prism:

                                   (3 x 4 x 6) inches

Find:-

What is the length of the diagonal from the point R to point S, to the nearest tenth of an inch?

Solution:-

- We will set up an origin with coordinates ( 0 , 0 , 0 ) at point R. Then the coordinates of point S would be ( 3 , 4 , 6 ).

- Then we will use the distance between two points formula in cartesian coordinate system:

                    Distance = \sqrt{(x_1 - x_2)^2 + (y_1 - y_2)^2 + (z_1 - z_2)^2}

Where the coordinates of two points ( x1 , y1 , z1 ) & ( x2 , y2 , z2 ).

- Using R( 0 , 0 , 0 ) & S( 3 , 4 , 6 ), the distance |RS| would be:

                   |RS| = \sqrt{(0 - 3)^2 + (0 - 4)^2 + (0 - 6)^2}\\\\|RS| = \sqrt{ 9 + 16 + 36}\\\\|RS| = \sqrt{61} = 7.81024

- The distance |RS| to nearest 10th of an inch is = 7.8 in  

4 0
3 years ago
Drag the ordered pair that are 5.5 units apart.
Alexus [3.1K]

Answer:

  (-1.5, -3.5) and (-1.5, 2)

Step-by-step explanation:

The x-coordinates in increasing order are ...

  -3, -1.5, 5

The distances between pairs of these coordinates are ...

  -1.5 -(-3) = 1.5

  5 -(-3) = 8

  5 -(-1.5) = 6.5

Clearly, any pair with x = 5 is too far away from any pair with a different x-value.

<u>∆x = 1.5</u>

If the distance between pairs is 5.5, then the distance formula tells us the y-coordinate differences for pairs with x-coordinates of -3 and -1.5 must be ...

  d = √((x2 -x1)^2 +(y2 -y1)^2)

  5.5 = √(1.5^2 +(y2 -y1)^2) . . . substitute known values

  30.25 = 2.25 +(y2 -y1)^2 . . . . square both sides

  √28 = (y2 -y1) . . . . . . . . . . . . . . subtract 2.25 and take the square root

This value is irrational. Clearly none of the y-coordinates is irrational, so there are no point pairs with x-coordinates -3 and -1.5 that are 5.5 units apart.

__

<u>∆x = 0</u>

If the x-coordinates are the same, then the y-coordinates must differ by 5.5 in order for the points to be 5.5 units apart. The coordinates in order are ...

  for x = -1.5, y = -3.5, 2, 2.5 . . . . . differences of 5.5, 6, 0.25

  for x = 5, y = -3.5, 1.5 . . . . . . . difference of 5

The only pair we can find that is 5.5 units apart is ...

  (-1.5, -3.5) and (-1.5, 2).

6 0
3 years ago
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