Answer:
The critical value for a 98% CI is z=2.33.
The 98% confidence interval for the mean is (187.76, 194.84).
Step-by-step explanation:
We have to develop a 98% confidence interval for the mean number of minutes per day that children between the age of 6 and 18 spend watching television per day.
We know the standard deveiation of the population (σ=21.5 min.).
The sample mean is 191.3 minutes, with a sample size n=200.
The z-value for a 98% CI is z=2.33, from the table of the standard normal distribution.
The margin of error is:
With this margin of error, we can calculate the lower and upper bounds of the CI:
The 98% confidence interval for the mean is (187.76, 194.84).
Answer:
A) 1 line of symmetry
Step-by-step explanation:
Answer:
15 more weeks
Step-by-step explanation:
425 - 125 (what shes already saved)
300 divided by 20 (amount shes saving each week)
Result is 15, so 15 more weeks.
Hope this helped :)
If you mean how many weeks total, 125 according to the 20 dollars a week would bring it 22 weeks i think.. since the answer answer is 21.2 weeks exactly when you divide 425 by 20.
2 is the answer because if you subtract 12 to 1 it will be 11 and time by 0 and it will be 0 add by 4 and divide it by 2 and it will be 2.
The most likely number of bags of peanuts she
sold is 20 bags of peanut at at $4 each
<h3>Equation</h3>
Kiyo:
94 = 10 + x
94 - 10 = x
84 = x
Aleja
94 = 14 + y
94 - 14 = y
80 = y
- Find the highest common factor of 84 and 80
80 = 1, 2, 4, 5, 8, 10, 16, 20, 40 and 80.
84 = 1, 2, 3, 4, 6, 7, 12, 14, 21, 28, 42 and 84
- The highest common factor is 4
80 ÷ 4 = 20 bags of peanut
84 ÷ 4 = 21 bags of peanut
Learn more about equation:
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