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Mice21 [21]
3 years ago
13

I'd appreciate it if you could help me

Biology
1 answer:
wel3 years ago
7 0

Answer:

A...?

Explanation:

I'm sorry hun but i'm not entirely sure about my answer and i would completely understand if you don't trust me. My answer is mostly my opinion and i'm sorry i don't have any proof to back up my claim...

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4 years ago
Sickle-cell trait is caused by a single defective allele, but sickle-cell disease only occurs in individuals that are homozygous
Pavel [41]

Answer:

6,25%

Explanation:

Considering that the couple has a trait of sickle cell anemia, we know that both are heterozygous for the disease (Aa) and therefore can have children with the following genotypes:

Parents: Aa X Aa

Children: AA(A x A), Aa(A x a), Aa (a x A) and aa(a x a)

Knowing that sickle cell anemia only occurs in homozygous individuals, the probability for children to have the disease according to each crossing is:

A x A = 1/4 = 25%

A x a = 1/4 = 25%

a x A = 1/4 = 25%

a x a = 1/4 = 25%

The probability of forming each homozygous child (aa) is 1/4 or 25%. Since they are two children, the probability of both having sickle cell anemia is calculated by multiplying the probability of each, so:

1/4 × 1/4 = 1/16 = 0.0625 = 6.25%

It is concluded that the probability of a heterozygous couple for sickle cell anemia to have two children with the disease is 6.25%.

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3 years ago
How do oceans influence weather and climate?
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Explanation:

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