Question

The sum of three consecutive integers is 21 larger than twice the smallest integer. find the integers.

Answer 1

Let the integers be x-1, x, x+1.

Given,

x -1 + x + x + 1 = 21 + 2(x - 1)

3x = 21 + 2x - 2

x = 19

Hence, the three integers are 18, 19 and 20.