We will solve using the law of sines as follows:
Now, we solve for X:
So, the length of X is sqrt(3).
Clarence measures the diameter of each tennis ball and a bag with a standard ruler. Unfortunately he uses the ruler and correctl
y so that each of his measurements is 0.2 inches too large. Clarence is data has a mean of 3.2 inches and a standard deviation of 0.1 inches find the mean and standard deviation of the corrected measurements in centimeters
1 answer:
Refer to the figure below.
Assume that there are n correct measurements
Because each measurement has an error of 0.2 in, the actual measurements are
From the figure, the analysis indicates that the correct mean is
μ = 3 in = 3*2.54 cm = 7.62 cm
The correct standard deviation is
2.934 in = 2.934*2.54 cm = 7.45 cm
Answer:
μ = 7.62 cm
σ = 7.45 cm
Assume that there are n correct measurements
Because each measurement has an error of 0.2 in, the actual measurements are
From the figure, the analysis indicates that the correct mean is
μ = 3 in = 3*2.54 cm = 7.62 cm
The correct standard deviation is
2.934 in = 2.934*2.54 cm = 7.45 cm
Answer:
μ = 7.62 cm
σ = 7.45 cm
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