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3 years ago

HELP PLEASE 20 points

Mathematics

1 answer:

STALIN [3.7K]3 years ago

7 0

Answer: first is 4 second is 5

Step-by-step explanation:

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PLZ HELP PLZ! TY! WILL GIVE BRAINLIEST TO WHOEVER ANSWERS

Marysya12 [62]

Take the y and x and 4 as a common factor and you will get 4xy(2yz+3x) the second one is the answer

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4 years ago

How can i solve this question

MAXImum [283]

It is really simple. The ratio between both the triangles is 7, so you just divide 49 by 7(it gives you 7) to get the value of x. The answer is option (a) 7.

Hope This Helped!

Good Luck!

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3 years ago

Cameron estimates that the math class will sell 200 calendars what will the total income be

Oduvanchick [21]

<span>2.50(200) + 500...you plug in 200 for x. 200 times 2.50 is 500. 500 plus 500 is 1000. the income is 1000.</span>

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3 years ago

In the equation 2x + 7 = 21, what is the value of x?<br> A.7 B.9 C.11 D.14

diamong [38]

The value of x is A.

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4 years ago

You have D dollars to buy fence to enclose a rectangular plot of land (see figure at right). The fence for the top and bottom co

alex41 [277]

The perimeter of the rectangular plot of land is given by the expression below

$P=2x+2y$

On the other hand, since the available money to buy fence is D dollars,

$\begin{gathered} D=4(2x)+3(2y) \\ \Rightarrow D=8x+6y \\ D\rightarrow\text{ constant} \end{gathered}$

Furthermore, the area of the enclosed land is given by

$A=xy$

Solving the second equation for x,

$\begin{gathered} D=8x+6y \\ \Rightarrow x=\frac{D-6y}{8} \end{gathered}$

Substituting into the equation for the area,

$\begin{gathered} A=(\frac{D-6y}{8})y \\ \Rightarrow A=\frac{D}{8}y-\frac{3}{4}y^2 \end{gathered}$

To find the maximum possible area, solve A'(y)=0, as shown below

$\begin{gathered} A^{\prime}(y)=0 \\ \Rightarrow\frac{D}{8}-\frac{3}{2}y=0 \\ \Rightarrow\frac{3}{2}y=\frac{D}{8} \\ \Rightarrow y=\frac{D}{12} \end{gathered}$

Therefore, the corresponding value of x is

$\begin{gathered} y=\frac{D}{12} \\ \Rightarrow x=\frac{D-6(\frac{D}{12})}{8}=\frac{D-\frac{D}{2}}{8}=\frac{D}{16} \end{gathered}$ <h2>Thus, the dimensions of the fence that maximize the area are x=D/16 and y=D/12.</h2><h2>As for the used money,</h2> $\begin{gathered} top,bottom:\frac{8D}{16}=\frac{D}{2} \\ Sides:\frac{6D}{12}=\frac{D}{2} \end{gathered}$ <h2>Half the money was used for the top and the bottom, while the other half was used for the sides.</h2>

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1 year ago