Write the expression 4^4(4^-7)(4) using a single exponent

f the length of side a is 12 centimeters, m= 36°, and m= 75°, what is the length of side b? Round your response to two decimal p

-Dominant- [34]

Answer:

Option C. is correct

Step-by-step explanation:

In the triangle ABC, vertices are A(12, 8), B(4, 8) and C(4, 14)

AB =

BC =

AC =

In triangle XYZ vertices are X(6,6), Y(4,12) and Z(10, 14)

XY =

YZ =

XZ =

In triangle MNO, vertices are M(4, 16), N(4, 8) and O(-2, 8)

MN =

MO =

NO =

In triangle JKL, vertices are J(14, -2), K(12,2) and L(20, 4)

JK =

KL =

JL =

Now we compare the sides for the congruence

Since AB = MN = 8

BC = NO = 6

AC = OM = 10

So ΔABC ≅ Δ MNO

Option C. is correct

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3 0

3 years ago

Given the function h(x), determine the functions which correctly decompose h(x) into component functions f(x) and g(x) so that h

nataly862011 [7]

$\text{Hi there! :)}$

$\large\boxed{g(x) = 7x + 2\text{ , } f(x) = \sqrt{x} - 10}$

$\text{h(x) = f(g(x)), so determine what g(x) was substituted into f(x):}\\\\\text{Given the equation } h(x) = \sqrt{7x +2}- 10:\\\\\text{In the part of the equation with a variable, we see that "7x + 2" is in a square root:}$

$\text{Therefore, we can say that g(x) = 7x + 2:}\\\\\text{If h(x) = f(7x + 2), then f(x) must be:}\\\\f(x) = \sqrt{x} - 10$

$\text{The respective functions would be:}\\\\g(x) = 7x + 2\\\\f(x) = \sqrt{x} - 10$

7 0

3 years ago

Multiply this expression :: -2/7 • (-3 5/8)

Helen [10]

Answer: 29/28

Step-by-step explanation:

-2/7 x (-3 5/8)

= -2/7 x -29/8

= 2/7 x 29/8 = 1/7 x 29/4

= 29/28

7 0

3 years ago

Let X denote the distance (m) that an animal moves from its birth site to the first territorial vacancy it encounters. Suppose t

andrezito [222]

Answer and Step-by-step explanation: For an exponential distribution, the probability distribution function is:

f(x) = λ. $e^{-\lambda.x}$

and the cumulative distribution function, which describes the probability distribution of a random variable X, is:

F(x) = 1 - $e^{-\lambda.x}$

(a) Probability of distance at most 100m, with λ = 0.0143:

F(100) = 1 - $e^{-0.0143.100}$

F(100) = 0.76

Probability of distance at most 200:

F(200) = 1 - $e^{-0.0143.200}$

F(200) = 0.94

Probability of distance between 100 and 200:

F(100≤X≤200) = F(200) - F(100)

F(100≤X≤200) = 0.94 - 0.76

F(100≤X≤200) = 0.18

(b) The mean, E(X), of a probability distribution is calculated by:

E(X) = $\frac{1}{\lambda}$

E(X) = $\frac{1}{0.0143}$

E(X) = 69.93

The standard deviation is the square root of variance,V(X), which is calculated by:

σ = $\sqrt{\frac{1}{\lambda^{2}} }$

σ = $\sqrt{\frac{1}{0.0143^{2}} }$

σ = 69.93

Distance exceeds the mean distance by more than 2σ:

P(X > 69.93+2.69.93) = P(X > 209.79)

P(X > 209.79) = 1 - P(X≤209.79)

P(X > 209.79) = 1 - F(209.79)

P(X > 209.79) = 1 - (1 - $e^{-0.0143*209.79}$ )

P(X > 209.79) = 0.0503

(c) Median is a point that divides the value in half. For a probability distribution:

P(X≤m) = 0.5

$\int\limits^m_0 f({x}) \, dx$ = 0.5

$\int\limits^m_0 {\lambda.e^{-\lambda.x}} \, dx$ = 0.5

$\lambda.\frac{e^{-\lambda.x}}{-\lambda}$ = $-e^{-\lambda.x} + e^{0}$

$1 - e^{-\lambda.m}$ = 0.5

$-e^{-\lambda.m}$ = - 0.5

ln( $e^{-0.0143.m}$ ) = ln(0.5)

-0.0143.m = - 0.0693

m = 48.46

6 0

4 years ago

From their location in the diagram, what are two possible values for m and n?

yarga [219]

M=6/5 and n = sqrt(2), is rational (but not an integer) and n is irrational.

The case with n = sqrt(9)=3, is not a solution. The case with m=4pi neither.

The last case is m = 6/2=3, integer, so neither works.

So, it is the one with m=6/5 and sqrt(2)

3 0

4 years ago