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2 years ago

A rectangle has an area of 3 3/4 square feet. the length is 1 1/2 . what is the width

Mathematics

1 answer:

Law Incorporation [45]2 years ago

8 0

Answer:

The answer is 2 1/2

Step-by-step explanation:

First you turn 3 3/4 into an improper fraction .To do that you multiply the denominator x the whole number + the numerator = 4x3=12 +3=15/4.

Then you turn 1 1/2 into an improper fraction .To do that you multiply the denominator x the whole number + the numerator =2x1+1=3/2

15/4 divided by 3/2 but get your answer you have to reverse 3/2 into 2/3 and you multiply instead of dividing .

15/4 x 2/3 =15 x2 = 30 , 4x3=12 so your answer will be 30/12 but it can be simplified because they are both multiple of 6 . So , 30 divided by 6 = 5 and 12 divided by 6 = 2 so then you answer is 5/2 but it is an improper fraction so you divide 5 by 2 and you get 2 and a remainder of 1/2=2 1/2

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Answer:

A: y = -2x + 2

B: 1100

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2 years ago

This week, we are covering relationships that can be approximated by linear equations. For instance, y = 453x + 3768 represents

lana [24]

Answer:

See explanation below.

Step-by-step explanation:

We assume that the data is given by :

x: 30, 30, 30, 50, 50, 50, 70,70, 70,90,90,90

y: 38, 43, 29, 32, 26, 33, 19, 27, 23, 14, 19, 21.

Where X represent the cost for scholarships in thousands of dollars and y represent the cost of life for an academic semester (The data comes from the web)

We can find the least-squares line appropriate for this data.

For this case we need to calculate the slope with the following formula:

$m=\frac{S_{xy}}{S_{xx}}$

Where:

$S_{xy}=\sum_{i=1}^n x_i y_i -\frac{(\sum_{i=1}^n x_i)(\sum_{i=1}^n y_i)}{n}$

$S_{xx}=\sum_{i=1}^n x^2_i -\frac{(\sum_{i=1}^n x_i)^2}{n}$

So we can find the sums like this:

$\sum_{i=1}^n x_i = 30+30+30+50+50+50+70+70+70+90+90+90=720$

$\sum_{i=1}^n y_i =38+43+29+32+26+33+19+27+23+14+19+21=324$

$\sum_{i=1}^n x^2_i =30^2+30^2+30^2+50^2+50^2+50^2+70^2+70^2+70^2+90^2+90^2+90^2=49200$

$\sum_{i=1}^n y^2_i =38^2+43^2+29^2+32^2+26^2+33^2+19^2+27^2+23^2+14^2+19^2+21^2=9540$

$\sum_{i=1}^n x_i y_i =30*38+30*43+30*29+50*32+50*26+50*33+70*19+70*27+70*23+90*14+90*19+90*21=17540$

With these we can find the sums:

$S_{xx}=\sum_{i=1}^n x^2_i -\frac{(\sum_{i=1}^n x_i)^2}{n}=49200-\frac{720^2}{12}=6000$

$S_{xy}=\sum_{i=1}^n x_i y_i -\frac{(\sum_{i=1}^n x_i)(\sum_{i=1}^n y_i)}=17540-\frac{720*324}{12}{12}=-1900$

And the slope would be:

$m=-\frac{1900}{6000}=-0.317$

Nowe we can find the means for x and y like this:

$\bar x= \frac{\sum x_i}{n}=\frac{720}{12}=60$

$\bar y= \frac{\sum y_i}{n}=\frac{324}{12}=27$

And we can find the intercept using this:

$b=\bar y -m \bar x=27-(-0.317*60)=46.02$

So the line would be given by:

$y=-0.317 x +46.02$

We have an inverse linear relationship since the slope is negative between the variables of interest.

8 0

3 years ago

What is the P(H,H,H,T,T) on 5 flips of a coin?<br><br> I need help

meriva

Answer:

The probability for Heads will be 60% or 3/5.

The probability for Tails will be 40% or 2/5.

Step-by-step explanation:

The coin flipped 5 times and landed on Heads 3 times. This shows that out of 5 situations, 3 situations were Heads. Therefore, the probability is 3/5.

The coin landed on Tails 2/5 times the coin was flipped, which is basically the probability.

4 0

2 years ago

1. Wendy wants to find the width, AB, of a river. She walks along the edge of the river 300 ft and marks point C. Then she walks

Ierofanga [76]

It can be deduced that the triangles are similar because the three internal angles are equal for both triangles.

<h3>How to solve the triangle?</h3>

It should be noted that the triangles are similar because the three internal angles are equal.

In this case, the ratio of the corresponding sides are equal and the corresponding angles are congruent.

The width of the river will be:

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AB = (300 × 50)/80

AB = 187.50 feet.

Learn more about triangles on:

brainly.com/question/17335144

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2 years ago

2. What is the place value of the "6" in the number: 181,452.836? *

matrenka [14]

A. tenths

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3 years ago