Answer:
this wont work
Step-by-step explanation:
kidding will type awnser shortly
Answer:

Step-by-step explanation:
The gradient = change in y / change in x
When the x value increases by 1, the y value decreases by 2 so -2 / 1 = -2
The y intercept is 4, so it is +4
(3r^-2s^3t^0)^-3
~~~~~~~~~~~~~~ r (s)
3
=1/3 r^7 s
~~~~~~~~~
27s^9
= r^7
~~~~~~~
81s^8
Answer is =r^7/ 81s^8
(x^2 - 3x - 10) * (x - 2) over
(x^2 - 6x + 5) * (x - 5)
(x - 5)(x + 2)(x - 2) over
(x - 5)(x - 1)(x - 5)
(x + 2)(x - 2) is the numerator
(x - 1)(x - 5) is the denominator
excluded values are 1 and 5
The cost of one rose bush is $2 and one day lily is $10.
Step-by-step explanation:
Let,
Cost of one rose bush = x
Cost of one day lily = y
According to given statement;
7x+6y=74 Eqn 1
7x+y=24 Eqn 2
Subtracting Eqn 2 from Eqn 1

Dividing both sides by 5

Putting y=10 in Eqn 1

Dividing both sides by 7

The cost of one rose bush is $2 and one day lily is $10.
Keywords: linear equation, elimination method
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