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storchak [24]
3 years ago
13

Daniel bought four bags of potatoes. The weight of the first bag was 2.6 pounds. The second bag weighed 0.4 pound less than twic

e the weight of the first bag. The third bag weighed 0.6 pound more than the first bag. The fourth bag weighed 0.3 pound less than the weight of the second bag. What is the average weight of the bags of potato es that Daniel bought? Round your answer to the nearest tenth.
Mathematics
1 answer:
ipn [44]3 years ago
8 0

Answer:

Average weight of the bags of potatoes is 3.8 pounds.

Step-by-step explanation:

Given:

Weight of the first bag, W_{1}=2.6 pounds.

Weight of the second bag is 0.4 pounds less than twice the weight of first bag. This means,

W_{2}=2W_{1}-0.4=2(2.6)-0.4=5.2-0.4=4.8\textrm{ pounds}

Weight of the third bag is 0.6 pounds more than that of the first bag. This means,

W_{3}=W_{1}+0.6=2.6+0.6=3.2\textrm{ pounds}

Weight of the fourth bag is 0.3 pounds less than that of the second bag. This means,

W_{4}=W_{2}-0.3=4.8-0.3=4.5\textrm{ pounds}

Therefore, the average weight of the bags of potatoes is given as the sum of all the weights and then divide the sum by 4. Therefore,

W_{average}=\frac{W_{1}+W_{2}+W_{3}+W_{4}}{4}=\frac{2.6+4.8+3.2+4.5}{2}=\frac{15.1}{4}=3.775\approx 3.8

Therefore, average weight of the bags of potatoes is 3.8 pounds.

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Evaluate S5 for 300 + 150 + 75 + … and select the correct answer below. 18.75 93.75 581.25 145.3125
Savatey [412]

we have that

300 + 150 + 75 +...

Let

a1=300\\ a2=150\\ a3=75

we know that

\frac{a2}{a1} =\frac{150}{300} \\\\ \frac{a2}{a1}=0.5 \\ \\ a2=a1*0.50

\frac{a3}{a2} =\frac{75}{150} \\\\ \frac{a3}{a2}=0.5 \\ \\ a3=a2*0.50

so

a(n+1)=an*0.50

Is a geometric sequence

Find the value of a4

a(4)=a3*0.50

a(4)=75*0.50

a(4)=37.5

Find the value of a5

a(5)=a4*0.50

a(5)=37.5*0.50

a(5)=18.75

Find S5

S5=a1+a2+a3+a4+a5\\ S5=300+150+75+37.5+18.75\\ S5=581.25

therefore

the answer is

581.25

Alternative Method

Applying the formula

S_n=\frac{a_1 (1-r^n)}{1-r} \\\\a_1=300 \\ r=\frac{1}{2}\\\\ S_5=\frac{300(1-(\frac{1}{2})^5)}{1-\frac{1}{2}}\\\\=\frac{300(1-\frac{1}{32})}{\frac{1}{2}}\\\\=\frac{300 \times \frac{31}{32}}{\frac{1}{2}}\\\\=\frac{75 \times \frac{31}{8}}{\frac{1}{2}}\\\\=\frac{\frac{2325}{8}}{\frac{1}{2}}\\\\=\frac{2325}{8} \times 2\\\\=\frac{2325}{4}\\\\=581 \frac{1}{4}\\\\=581.25

therefore

the answer is

581.25

6 0
2 years ago
Read 2 more answers
Find the slope of the line that passes through (40,3000) and (60, 4000).
iragen [17]

Answer:

m=50

General Formulas and Concepts:

<u>Pre-Alg</u>

  • Order of Operations: BPEMDAS

<u>Algebra I</u>

  • Slope Formula: m=\frac{y_2-y_1}{x_2-x_1}

Step-by-step explanation:

<u>Step 1: Define</u>

Point (40, 3000)

Point (60, 4000)

<u>Step 2: Find slope </u><em><u>m</u></em>

  1. Substitute:                    m=\frac{4000-3000}{60-40}
  2. Subtract:                       m=\frac{1000}{20}
  3. Divide:                          m=50
3 0
3 years ago
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