the tens digit of a 2 digit number is twice the units digit. The sum of the digits is 12. Find the original number
1 answer:
You might be interested in
log(x+3)(2x+3)+log( x+3)( x+5) =2
logx(2x+3)+3(2x+3 )+log x(x+5)+3(x+5)
log(x+3)(2x+3)+log( x+3)( x+5) =2
logx(2x+3)+3(2x+3 )+log x(x+5)+3(x+5)