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tino4ka555 [31]
3 years ago
11

Work out the area of the trapezium ABDE. B 9 cm 6 cm 8 cm →D E

Mathematics
1 answer:
Evgen [1.6K]3 years ago
8 0

Answer:

Area of the trapezium ABDE = 30 cm²

Step-by-step explanation:

Area of a trapezium = \frac{1}{2}(b_1+b_2)h

Here, b_1 and b_2 are the parallel sides of the trapezium

h = Distance between the parallel sides

From the picture attached,

ΔCAE and ΔCBD are the similar triangles.

So by the property of similarity their sides will be proportional.

\frac{AE}{BD}= \frac{CE}{CD}

\frac{9}{6}=\frac{CE}{8}

CE = \frac{9\times 8}{6}

CE = 12 cm

Therefore, DE = CE - CD

DE = 12 - 8 = 4 cm

Now area of trapezium ABDE = \frac{1}{2}(AE+BD)(DE)

                                                  = \frac{1}{2}(6+9)4

                                                  = 30 cm²

Therefore, area of the trapezium ABDE = 30 cm²

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Answer:

The value of n = -10  

Step-by-step explanation:

Given the points

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so substituting the values

      10   =  [0 - n] / [4 - 3]

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If the risk-free rate is 7 percent, the expected return on the market is 10 percent, and the expected return on Security J is 13
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4 years ago
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ivann1987 [24]
Given list of values
A = {23, 34, 19, 10, 9, 20, 40, 43, 28, 29, 36, 13, 27, 23, 36, 37, 7}

Sort list A to get list B
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The smallest value is 7, so the min is 7
The largest value is 43, so the max is 43

Look through list B to find the middle-most value. What you can do is cross off each pair of outer values (see figure 1 in the attached images) until you are left with the middle value
Or you can note how there are 17 values so the median is at slot 9 (there are 8 values below the median; 8 values above the median; the 8 is from 17/2 = 8.5)

Once you know the median is 27, we split the list B into two parts
The first part, we'll call it L for lower half is
L = {7, 9, 10, 13, 19, 20, 23, 23}
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The median of list L is 16 because its the midway point between 13 and 19. We can compute (13+19)/2 = 32/2 = 16. This is the value of Q1

The upper half U is
U = {28, 29, 34, 36, 36, 37, 40, 43}
this list shows all the values larger than the median.
The value of Q3 is 36. We find the midpoint of 36 and 36 which is just 36.
The value of Q3 is the same as the median of list U

------------------------------------------------

Five Number Summary:
Min = 7
Q1 = 16
Median = 27
Q3 = 36
Max = 43

This five number summary is then used to construct the box-and-whisker plot. See figure 2 in the attached images. The diagram shows how each piece of the boxplot is put together (eg: the left edge of the box is the value of Q1). 

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