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Scrat [10]
3 years ago
9

Sec²θ=4+2tan²θFind θ​

Mathematics
1 answer:
Marina86 [1]3 years ago
5 0

Recall the Pythagorean identity,

\sec^2\theta=1+\tan^2\theta

So we have

\sec^2\theta=4+2\tan^2\theta

1+\tan^2\theta=4+2\tan^2\theta

-3=\tan^2\theta

But squaring any real number always gives a non-negative number, so there are no real solutions to this equation.

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