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Aleksandr [31]
3 years ago
6

There were 4 car races on saturdayand 3 on Sunday. If there were 9 cars racing in each race, how many cars raced over the two da

ys?
Mathematics
1 answer:
sergij07 [2.7K]3 years ago
3 0
There were 63 cars in each race.

You do the distributive property which would look like 9(3+4). Once you distribute that you should have 27+36. You add that and get the answer of 63. Hope this helps!
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The probability of choosing the red card will be 0.03%

<h3>What is probability?</h3>

In this situation, Mickey should have drawn the first 7 cards that are not diamond and then on the 8th attempt she should draw an ace.

Let A be the event of drawing 7 cards which are not diamond and B the event of drawing an ace card. therefore the required probability is

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Now, there are 13 diamonds and 39 other cards. Hence,

P(A)=(13/39)⁷=0.1335

After drawing 7 non-diamond cards, the 8th card must be a diamond. Hence,

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Hence, P(A∩B)=P(A)*P(B)=0.1335*0.25=0.033(approximately 0.03,i.e. 3%)

Therefore the probability that Mickey will draw her first red diamond on the 8th attempt is 0.03%

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2 years ago
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Step 1: Simplify both sides of the inequality.

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