If x,y and z are the first three terms of an geometric sequence, show that x^2,y^2 and z^2 form another geometric sequence
1 answer:
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<h3><u>Answer with explanation:</u></h3>
From the box and whisker plot of seventh grade we have:
The minimum value =6
First quartile or lower quartile i.e. = 14
Median or second quartile i.e. = 18
Third quartile or upper quartile i.e. =22
and maximum value = 26
From the box and whisker plot of eighth grade we have:
The minimum value =22
First quartile or lower quartile i.e. = 26
Median or second quartile i.e. = 30
Third quartile or upper quartile i.e. = 34
and maximum value = 38
a)
The overlap of the two sets of data is as follows.
- The upper quartile or third quartile of seventh grade is same as the minimum value of the data of eighth grade.
- And the maximum value of seventh grade is same as the lower quartile of eighth grade.
b)
IQR is calculated as the difference of the Upper quartile and the lower quartile
i.e.
so, IQR of seventh grade is:
22-14=8
IQR of seventh grade=8
IQR of eighth grade is:
34-26=8
Hence, IQR of eighth grade=8
c)
The difference of the median of the two data sets is:
30-18=12
Hence, the difference of median is: 12
d)
As the IQR of both the sets is same i.e. 8.
Hence, the number that must be multiplied by IQR so that it is equal to the difference between the medians of the two sets is:
Hence, the number is : 1.5
Brad have 19 quarters and 27 nickels.
Step-by-step explanation:
Given,
Total worth of nickels and quarters = $6.10 = 6.10*100 = 610 cents
One quarter = 25 cents
One nickel = 5 cents
Let,
x represent the number of quarters.
y represent the number of nickels.
According to given statement;
25x+5y=610 Eqn 1
y = x+8 Eqn 2
Putting value of y from Eqn 1 in Eqn 2
Dividing both sides by 30
Putting x=19 in Eqn 2
Brad have 19 quarters and 27 nickels.
Keywords: linear equation, subtraction
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Answer:
The remainder is -2.
Step-by-step explanation:
According to the Polynomial Remainder Theorem, if we divide a polynomial P(x) by a binomial (<em>x</em> - <em>a</em>), then the remainder of the operation will be given by P(a).
Our polynomial is:
And we want to find the remainder when it's divided by the binomial:
We can rewrite our divisor as (<em>x</em> - (-1)). Hence, <em>a</em> = -1.
Then by the PRT, the remainder will be:
The remainder is -2.