Ask question

Ask question

All categories

2 years ago

5

If x,y and z are the first three terms of an geometric sequence, show that x^2,y^2 and z^2 form another geometric sequence

1 answer:

olganol [36]2 years ago

8 0

<span>x y z are in geometric
x/y = y/z
OR y^2=xz

x^2, y^2, z^2

x^2, xz, z^2
If they are in geometric sequence then
xz/x^2 = z^2/xz
z/x = z/x
The ratios are common
so x^2,y^2 & z^2 is a GP.</span>

You might be interested in

The center of the circle is at (-2,-7) and its radius is 36.

Vanyuwa [196]

Standard form for circle with radius r and center (h,k) is
(x-h)^2+(y-k)^2=r^2

r=36
center at -2,-7
(x-(-2))^2+(y-(-7))^2=36^2
(x+2)^2+(y+7)^2=1296

firts option

6 0

2 years ago

Review the graph. What is the component form and direction of the vector shown

Charra [1.4K]

Answer:

<-7,3> and 157 degrees

got it right :) hope this helped

4 0

2 years ago

Read 2 more answers

Can someone please help me. I need help on the 5 one

soldi70 [24.7K]

Answer:

The second option

Step-by-step explanation:

On the right hand side you have all the multiples of 4, on the left hand side you have 5

The multiples of four are ...,-8,-4,0,4,8,....

so the simbol that means that 5 is not an element of the multiples of four is the second option.

4 0

3 years ago

If a 9-foot flagpole casts a 6-foot shadow, how tall is the woman who casts a 4-foot shadow?

FinnZ [79.3K]

It is A because if you subtract 9 and 6 you get 3 and then you add the 4 and get 7

6 0

3 years ago

Solve for x: 5/x^2-4+2/x=2/x-2

IRINA_888 [86]

$\dfrac{5}{x^2 - 4} + \dfrac{2}{x} = \dfrac{2}{x - 2}$

$\dfrac{5}{(x + 2)(x - 2)} + \dfrac{2}{x} = \dfrac{2}{x - 2}$

$\dfrac{5}{(x + 2)(x - 2)} \times x(x + 2)(x - 2) + \dfrac{2}{x} \times x(x + 2)(x - 2) = \dfrac{2}{x - 2} \times x(x + 2)(x - 2)$

$5x + 2(x + 2)(x - 2) = 2x(x + 2)$

$5x + 2(x^2 - 4) = 2x^2 + 4x$

$5x + 2x^2 - 8 = 2x^2 + 4x$

$5x - 8 = 4x$

$x - 8 = 0$

$x = 8$

Now we look at the common denominator.

It is x(x + 2)(x - 2).

x cannot be zero, -2 or 2 because that would cause a zero in the denominator.

Since we get x = 8, and x = 8 does not have to be excluded from the domain, the answer is x = 8.

Answer: x = 8

6 0

3 years ago