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olya-2409 [2.1K]
3 years ago
9

Please help me with this and thank you

Mathematics
1 answer:
dimaraw [331]3 years ago
6 0

Answer:c

Step-by-step explanation:

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PLZ HELP OOOOHHH<br><br> Solve for X<br><br> -1/5(x-4)= -2<br><br> x=[_]
zavuch27 [327]

Answer:

X = 10 + 4   Simplified: X = 14

Step-by-step explanation:

-1/5 (x - 4) = -2

distributive property

(-1/5 · x) + (-1/5 · -4) = -2

simplify

-1/5x + 0.8 = -2

multiply each side by -5

X + -4 = 10

simplify

X - 4 = 10

an

5 0
2 years ago
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Is 43 a two digit odd number?
Snowcat [4.5K]
Yes.  The '4' and the '3' are its two digits, and the '3' in the last place
identifies it as an odd number (not  evenly divisible by 2).
8 0
2 years ago
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What is 70 in standard form?​
Novosadov [1.4K]

Answer:

7 \times  {10}^{2}

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6 0
2 years ago
What is the simplest form for 10/42
QveST [7]


2 goes into both numbers, so divide both by 2;

10 ÷ 2 = 5

42 ÷ 2 = 21

so 10/42 in simplest form is: 5/21

7 0
2 years ago
To find the extreme values of a function​ f(x,y) on a curve xequals​x(t), yequals​y(t), treat f as a function of the single vari
pychu [463]

Answer:

Absolute maximum is 2  

Absolute minimum at -2

Step-by-step explanation:

The given parametric functions are:

x=2\cos t,y=2\sin t

By the chain rule:

f'(t)=\frac{\frac{dy}{dt} }{\frac{dx}{dt} }

\frac{df}{dt} =\frac{2 \cos t}{-2\sin t} =-\cot(t)

At fixed points, f'(t)=0

\implies -\cot (t)=0

This gives t=\frac{\pi}{2} ,\frac{3\pi}{2} on 0\le t\le 2\pi

This implies that the extreme points are (2\cos \frac{\pi}{2}, 2\sin \frac{\pi}{2})=(0,2) and (2\cos \frac{3\pi}{2}, 2\sin \frac{3\pi}{2})=(0,-2)

By eliminating the parameter, we have x^2+y^2=4

This is a circle with radius 2, centered at the origin.

Hence (0,2) is an absolute maximum ,at t=\frac{\pi}{2} and (0,-2) is an absolute minimum at  t=\frac{3\pi}{2}

7 0
3 years ago
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