You could do the question the way it is written, but it is far easier to bring the negative power up to the numerator.
y= x^2 - 3. The derivative of that is
dy/dx = 2x The three is a constant and is always dropped when a derivative is taken
d(-3)/dx = 0
If you are a purist and want to solve the question the way it is written, you could do it this way.
dy/dx = d(1)/dx x^-2 - d(x^-2)/dx * 1
======================
(x^-2)^2
dy/dx = - (-2 x^ - 3) / x^-4
dy/dx = 2 x^-3 * x^4
dy/dx = 2 x^(-3 + 4)
dy/dx = 2x ^ 1
dy/dx = 2x <<<<< answer
You didn't supply any rules or constraints so.... 1 in., 1 in., and 1 in.
You can use the Pythagorean Theorem to check if the side lengths are appropriate.
–this is true.
Answer:
Hope this will help you......
Answer:
b = a + 2 or b = 2 - a
Step-by-step explanation:
Solve for b:
-4 + a^2 + 4 b - b^2 = 0
The left hand side factors into a product with two terms:
(2 + a - b) (-2 + a + b) = 0
Split into two equations:
2 + a - b = 0 or -2 + a + b = 0
Subtract a + 2 from both sides:
-b = -a - 2 or -2 + a + b = 0
Multiply both sides by -1:
b = a + 2 or -2 + a + b = 0
Subtract a - 2 from both sides:
Answer:
b = a + 2 or b = 2 - a
