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kow [346]
3 years ago
7

radio gives local weather updates every 18 minutes. the first update is at 2:00pm. you turn the radio on at 5:30pm. how long wil

l you have to wait for the next local weather update?
Mathematics
2 answers:
Black_prince [1.1K]3 years ago
8 0
So this is just my guess. Sorry if It turns out incorrect. 
If at 2:00pm you hear the first weather update, and every 18 minutes you get a new update then you just keep adding 18minutes to your time. That's what I did.  Hopefully this makes sence to you.  
2:00+18= 2:18pm you have 2 updates, 2:36pm you have 3 updates, and evnetually at 5:20pm you will have a total 12 updates. The girft here is strange though because it is asking "How long will you have to wait for the next local uodate?" Well add 18 to 5:20pm. That equals 5:38pm. But, you turn the radio on at 5:30pm. That means you will have to wait 8 more minutes until the next update comes on.
nekit [7.7K]3 years ago
3 0
Youll have to wait 10 mins
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Please help! see attached
nikdorinn [45]

Answer:

  1. The lowest value of the confidence interval is 0.5262 or 52.62%
  2. The highest value of the confidence interval is 0.5538 or 55.38%

Step-by-step explanation:

Here you estimate the proportion of people in the population that said did not have children under 18 living at home.It can also be given as a percentage.

The general expression to apply here is;

C.I=p+-z*\sqrt{\frac{p(1-p)}{n} }

where ;

p=sample proportion

n=sample size

z*=value of z* from the standard normal distribution for 95% confidence level

Given;

n=5000

<u>Find p</u>

From the question 54% of people chosen said they did not have children under 18 living at home

\frac{54}{100} *5000 = 2700\\\\p=\frac{2700}{5000} =0.54

<u>To calculate the 95% confidence interval, follow the steps below;</u>

  • Find the value of z* from the z*-value table

The value of z* from the table is 1.96

  • calculate the sample proportion p

The value of p=0.54 as calculated above

  • Find p(1-p)

0.54(1-0.54)=0.2484

  • Find p(1-p)/n

Divide the value of p(1-p) with the sample size, n

\frac{0.2448}{5000} =0.00004968

  • Find the square-root of p(1-p)/n

=\sqrt{0.00004968} =0.007048

  • Find the margin of error

Here multiply the square-root of p(1-p)/n by the z*

=0.007048*1.96=0.0138

The 95% confidence interval for the lower end value is p-margin of error

=0.54-0.0138=0.5262

The 95% confidence interval for the upper end value is p+margin of error

0.54+0.0138=0.5538

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