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geniusboy [140]
3 years ago
12

2(6-x)=3 please help

Mathematics
2 answers:
enot [183]3 years ago
4 0

Answer:

<u><em>x = 4.5</em></u>

Step-by-step explanation:

Let's solve this together!

<em><u>First you would want to multiply 6 and x:</u></em>

6×2 = 12

x×2 = 2x

<em><u>Then you would want to subtract 12 from 3:</u></em>

3+12 = 9

<u><em>Then divide 9 by 2:</em></u>

9÷2 = 4.5

<h2><u><em>x=4.5</em></u></h2>

That's it!

Hope this helped! :)

soldi70 [24.7K]3 years ago
3 0
It’s impossible what are you doing Distributed property or solving for x?
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The expression into a single logarithm is log[(x)^{10}][(2)^{30}]

Step-by-step explanation:

Let us revise some logarithmic rules

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∵ 10 log(x) + 5 log(64)

- At first re-write 10 log(x)

∴  10 log(x) = log(x)^{10}

- Then re-write 5 log(64)

∴  5 log(64) = log(64)^{5}

∴ 10 log(x) + 5 log(64) = log(x)^{10} + log(64)^{5}

- Use the 3rd rule above to make it single logarithm

∵ log(x)^{10} + log(64)^{5} = log[(x)^{10}][(64)^{5}]

∴ 10 log(x) + 5 log(64) = log[(x)^{10}][(64)^{5}]

∵ 64 = 2 × 2 × 2 × 2 × 2 × 2

∴ We can write 64 as 2^{6}

∴ (64)^{5}=(2^{6})^{5}

- Multiply the two powers of 2

∴ (64)^{5}=(2)^{30}

∴ 10 log(x) + 5 log(64) = log[(x)^{10}][(2)^{30}]

The expression into a single logarithm is log[(x)^{10}][(2)^{30}]

Learn more:

You can learn more about the logarithmic functions in brainly.com/question/11921476

#LearnwithBrainly

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