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hram777 [196]
2 years ago
13

A tree graph can contain a circuit. True or False

Mathematics
1 answer:
Ugo [173]2 years ago
7 0
This answer is false
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A charity gala is held in a hotel ballroom each year. The cost is $150 for the ballroom and an
Serga [27]

Answer: x=100$

Step-by-step explanation:

use the slope formula

y=mx+b

plug in what you have

y=2400, m=22.50x, b=150

solve for x

2400=22.50x+150

subtract 150 from both sides

2250=22.50x

divide 22.50 x from both sides

x=100 people

don't forget your units :)

5 0
2 years ago
Write the equation of the line in slope-intercept form.
Natasha_Volkova [10]

Answer:

y=-1/2x-2

Step-by-step explanation:

8 0
2 years ago
Read 2 more answers
In triangle EFG, m of E = 30 degrees, m of F = 60 degrees, and m of G = 90 degrees. Which of the following statements about tria
Effectus [21]

Answer:

A. EG = √3 × FG

D. EG = √3/2 × EF

E. EF = 2 × FG

Step-by-step explanation:

∵ tan 60 = √3

∵ tan60 = EG/GF

∴ EG/GF = √3

∴ EG = √3 × GF ⇒ A

∵ m∠F = 60°

∵ sin60 = √3/2

∵ sin 60 = EG/EF

∴ √3/2 = EG/EF

∴ EG = √3/2 × EF ⇒ D

∵ cos60 = 1/2

∵ cos60 = GF/EF

∴ GF/EF = 1/2

∴ EF = 2 × GF ⇒ E

8 0
3 years ago
Read 2 more answers
Consider the functions f and g defined by \[f(x) = \sqrt{\dfrac{x+1}{x-1}}\qquad\qquad\text{and}\qquad\qquad g(x) = \dfrac{\sqrt
tino4ka555 [31]

Answer:

The given functions are not same because the domain of both functions are different.

Step-by-step explanation:

The given functions are

f(x)= \sqrt{\dfrac{x+1}{x-1}}

g(x) = \dfrac{\sqrt{x+1}}{\sqrt{x-1}}

First find the domain of both functions. Radicand can not be negative.

Domain of f(x):

\dfrac{x+1}{x-1}>0

This is possible if both numerator or denominator are either positive or negative.

Case 1: Both numerator or denominator are positive.

x+1\geq 0\Rightarrow x\geq -1

x-1\geq 0\Rightarrow x\geq 1

So, the function is defined for x≥1.

Case 2: Both numerator or denominator are negative.

x+1\leq 0\Rightarrow x\leq -1

x-1\leq 0\Rightarrow x\leq 1

So, the function is defined for x≤-1.

From case 1 and 2 the domain of the function f(x) is (-∞,-1]∪[1,∞).

Domain of g(x):

x+1\geq 0\Rightarrow x\geq -1

x-1\geq 0\Rightarrow x\geq 1

So, the function is defined for x≥1.

So, domain of g(x) is [1,∞).

Therefore, the given functions are not same because the domain of both functions are different.

4 0
3 years ago
i am doing integers and the question is Michael withdrew$60 from his checking account name the integer that represent the situat
Slav-nsk [51]
X-60 WITH X BEING THE BANK ACCOUNT TOTAL - THE WITHDRAWAL DO U HAVE ANY ANSWER CHOICES?

5 0
3 years ago
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