a^2 + b^2 = c^2
Let c = hypotenuse = 2x
One of the legs = x. Let a or b = x.
I will let a = x. We can then say that b = 3.
3^2 + x^2 = (2x)^2
9 + x^2 = 4x^2
9 = 4x^2 - x^2
9 = 2x^2
9/2 = x^2
sqrt{9/2} = sqrt{x^2}
3/sqrt{2} = x
Rational denominator.
[3•sqrt{2}]/2 = x = a
Side 3 is given to be 3 feet. So, b = 3.
Hypotenuse = 2x
Hypotenuse = 2([3•sqrt{2}]/2)
Hypotenuse = 3•sqrt{2}
Understand?
The three sides are 3, [3•sqrt{2}]/2 and
3•sqrt{2}.
Answer: 5-6i
The rule is that if f(x) has real number coefficients, then a root of x = a+bi pairs up with its conjugate pair of x = a - bi. In this case, a = 5 and b = 6.
Answer:
D
Step-by-step explanation:
Perimeter = (2)(length) + (2)(height)
Let's call the width x and the length y
Therefore perimeter = (2x)(2) + (5y)(2)= 4x+10y
2x÷(4x+10y) is the answer :)
He had $12.50 left because you do
1.25 + 5= 6.25 and because he spent half earlier you would multiply by two to get 12.5
