All categories

3 years ago

Find both solutions for the variable a^2-8a-48=0

Mathematics

1 answer:

Ludmilka [50]3 years ago

8 0

A^2-8a-48=0
factor
(a+4)(a-12)=0
set each equal to 0
a+4=0 a-12=0

a=-4,12

You might be interested in

Solve for y in the following equation.

Tju [1.3M]

Answer:

$y = \frac{z^2 - x}{2}$

Step-by-step explanation:

Given:

$\sqrt{x + 2y} = z$

Required:

Solve for y (make y the subject of the formula)

SOLUTION:

$\sqrt{x + 2y} = z$

Square both sides

$(\sqrt{x + 2y})^2 = z^2$

$x + 2y = z^2$

Subtract both sides by x

$2y = z^2 - x$

Divide both sides by 2

$y = \frac{z^2 - x}{2}$

5 0

3 years ago

-8<br><img src="https://tex.z-dn.net/?f=%20-%208%20%5Cgeqslant%203%20%2B%20h2" id="TexFormula1" title=" - 8 \geqslant 3 + h2" al

torisob [31]

Answer:

2h-91 ?

Step-by-step explanation:

3 0

3 years ago

Pls help 40 points<br>this is my last chance to get extra points pls serious answers

Alja [10]

Answer:

I think it is A or D

Step-by-step explanation:

I dont know because for a range to be determined, you must go at where the lowest point the function goes and the highest point it reaches, and the lowest is 250,000 and the highest is 1,000,000 but it says

250,000 < y < 1,000,000 and the A option says 0 < x < 110, I dont know but it is not b and c, I'm sorry if I'm wrong

8 0

4 years ago

The length of human pregnancies from conception to birth varies according to an approximately normal distribution with a mean of

Varvara68 [4.7K]

Answer:

A) 68.33%

B) (234, 298)

Step-by-step explanation:

We have that the mean is 266 days (m) and the standard deviation is 16 days (sd), so we are asked:

A. P (250 x < 282)

P ((x1 - m) / sd < x < (x2 - m) / sd)

P ((250 - 266) / 16 < x < (282 - 266) / 16)

P (- 1 < z < 1)

P (z < 1) - P (-1 < z)

If we look in the normal distribution table we have to:

P (-1 < z) = 0.1587

P (z < 1) = 0.8413

replacing

0.8413 - 0.1587 = 0.6833

The percentage of pregnancies last between 250 and 282 days is 68.33%

B. We apply the experimental formula of 68-95-99.7

For middle 95% it is:

(m - 2 * sd, m + 2 * sd)

Thus,

m - 2 * sd <x <m + 2 * sd

we replace

266 - 2 * 16 <x <266 + 2 * 16

234 <x <298

That is, the interval would be (234, 298)

6 0

3 years ago

About 16 % of the population of a large country is allergic to pollen. If two people are randomly selected, what is the probabil

Vinvika [58]

Answer:

(a) 0.0256

(b) 0.2944

Step-by-step explanation:

For solving this exercise we can apply the binomial distribution. The equation that give as the probability is:

$P(x,n,p)=(nCx)*p^{x} *(1-p)^{n-x}$

Where n is the number of identical events, p is the probability that the event has a success and x is the number of success in the n identical events.

Additionally, nCx is calculated as:

$nCx=\frac{n!}{x!(n-x)!}$

So, in this case we have 2 identical events because we are going to select two people randomly and the probability p of success is the probability that the person is allergic to pollen and this probability is 16%.

Then, for the first case, x is 2 because their are asking for the probability that both are allergic to pollen. Replacing the values of x, n and p we get:

$P(2,2,0.16)=(2C2)*0.16^{2} *(1-0.16)^{2-2}$

P(2,2,0.16)=0.0256

For the second case, their are asking for the probability that at least one is allergic to pollen, that means that we need to sum the probability that both are allergic to pollen with the probability that just one is allergic to pollen.

Using the same equation to calculate P(1,2,0.16) we get:

$P(1,2,0.16)=(2C1)*0.16^{1} *(1-0.16)^{2-1}$

P(1,2,0.16)=0.2688

So, the probability that at least one person is allergic to pollen is 0.2944 and it is calculated as:

0.0256 + 0.2688 = 0.2944

7 0

3 years ago