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Ira Lisetskai [31]
3 years ago
8

A class has 4 boys and 10 girls. What is the ratio in simplest form that compares number of boys to total number of students?

Mathematics
1 answer:
Alenkinab [10]3 years ago
4 0

C. The answer is C because the total amount of students is 14, and there are 4 boys, which makes the ratio 4 boys to 14 students in total. 4 and 14 are both divisable by 2, so divide 4 to get 2 and divide 14 to get 7. This leaves you with 2 and 7. The ratio would be 2 boys to 7 total students. Hope this helped

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Identify the zero(s) of the function graphed below
k0ka [10]

Answer:

Step-by-step explanation:

The zeros are the values of x for which y=0.

The zero of this graph is x=1.

8 0
2 years ago
I know y= 40 but what is x ?
puteri [66]

Answer:

x = 67; y = 40

Step-by-step explanation:

You are correct with y. Angles y + 23 and 63 are vertical, so they are congruent. That gives you y + 23 = 63, which gives y = 40.

To find x, look at angles 2x - 17 and 63.

They are adjacent angles whose outside rays lie on a line. Angles like these are called a linear pair, and they are supplementary. That means their measures add up to 180 deg.

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3 years ago
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5 0
3 years ago
Read 2 more answers
Easy Cooking is a cooking supply company. Last year, the company sold a total of 5,340 ovens. This year, they sold 7,743 ovens.
jenyasd209 [6]

Answer:

45%

Step-by-step explanation:

Given data

Last year, the company sold a total of 5,340 ovens

This year, they sold 7,743 ovens

Percent increase=   final-initial/initial*100

substitute

Percent increase=  7,743-5,340/5,340*100

Percent increase= 2403/5,340*100

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Hence the increase is 45%

7 0
3 years ago
5. Solve using any method.<br> y = -x + 8<br> y=x+4
vlada-n [284]

Answer:

<h2>x = 2, y = 6 → (2, 6)</h2>

Step-by-step explanation:

\bold{ELIMINATION\ METHOD}\\\\\left\{\begin{array}{ccc}y=-x+8\\y=x+4&\TEXT{change the signs}\end{array}\right\\\underline{+\left\{\begin{array}{ccc}y=-x+8\\-y=-x-4\end{array}\right}\qquad\text{add both sides of the equations}\\.\qquad0=-2x+4\qquad\text{add}\ 2x\ \text{to both sides}\\.\qquad2x=4\qquad\text{divide both sides by 2}\\.\qquad\boxed{x=2}\\\\\text{Put it to the second equation}\\y=2+4\\\boxed{y=6}

\bold{SUBSTITUTION\ METHOD}\\\\\left\{\begin{array}{ccc}y=-x+8&(1)\\y=x+4&(2)\end{array}\right\\\\\text{Substitute (1) to (2)}\\\\-x+8=x+4\qquad\text{subtract 8 from both sides}\\-x=x-4\qquad\text{subtract}\ x\ \text{from both sides}\\-x-x=-4\\-2x=-4\qquad\text{divide both sides by (-2)}\\\boxed{x=2}\\\\\text{Put it to the second equation}\\y=2+4\\\boxed{y=6}

7 0
3 years ago
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