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Pepsi [2]
3 years ago
9

G(x)=2x^2+3x+6 find g(p+3)

Mathematics
1 answer:
hichkok12 [17]3 years ago
5 0
We're finding the function of (p+3), which means wherever there's an x, we're replacing it with (p+3).
2 (p+3)^2 + 3 (p+3) + 6
Foil out (p+3)^2.
2 (p^2 + 6p + 9) + 3 (p+3) + 6
Distribute.
2p^2 + 12p + 18 + 3p + 9 + 6
Add like terms.
g (p+3) = 2p^2 + 15p + 33
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John Calipari, head basketball coach for the 2012 national champion University of Kentucky Wildcats, is the highest paid coach i
MrRissso [65]

Answer:

A) sample mean = $1.36 million

B) standard deviation = $0.9189 million

C) confidence interval = ($1.93 million , $0.79 million)

*since the sample size is very small, the confidence interval is not valid.

Step-by-step explanation:

samples:

  1. $2.7 million
  2. $2.4 million
  3. $2.2 million
  4. $2 million
  5. $1.5 million
  6. $1.5 million
  7. $0.5 million
  8. $0.5 million
  9. $0.2 million
  10. $0.1 million

sample mean = $1.36 million

the standard deviation:

  • $2.7 million - $1.36 million = 1.34² = 1.7956
  • $2.4 million - $1.36 million = 1.04² = 1.0816
  • $2.2 million - $1.36 million = 0.84² = 0.7056
  • $2 million - $1.36 million = 0.64² = 0.4096
  • $1.5 million - $1.36 million = 0.14² = 0.0196
  • $1.5 million - $1.36 million = 0.14² = 0.0196
  • $0.5 million - $1.36 million = -0.86² = 0.7396
  • $0.5 million - $1.36 million = -0.86² = 0.7396
  • $0.2 million - $1.36 million = -1.16² = 1.3456
  • $0.1 million - $1.36 million = -1.26² = 1.5876
  • total $8.444 million / 10 = $0.8444 million

standard deviation = √0.8444 = 0.9189

95% confidence interval = mean +/- 1.96 standard deviations/√n:

$1.36 million + [(1.96 x $0.9189 million)/√10] = $1.36 million + $0.57 million = $1.93 million

$1.36 million - $0.57 million = $0.79 million

7 0
3 years ago
Assume that a random sample of 4 Goldfinch birds are going to be used to test the above hypothesis. Compute the largest value of
Misha Larkins [42]

This question is incomplete, the complete question is;

Assume that body masses of Goldfinch birds follow a normal distribution, with a standard deviation equal to 0.04 oz. An ornithologist who would like to make some inference about the average body mass of the Goldfinch birds. In particular, at a significance level of 0.01, she would like to test the null hypothesis H₀: Average body mass of the Goldfinch birds is 0.5 oz, against the alternative claim that average body size is less than 0.5 oz.

      Assume that a random sample of 4 Goldfinch birds are going to be used to test the above hypothesis. Compute the largest value of the sample mean, that will allow the experimenter reject the null and prove the alternative at significance level 0.01. For this problem, make sure that your solution includes all steps of your computation. You will not earn points if you just use a formula

Answer: the largest value of the sample mean that will enable the experimenter to reject the null hypothesis is 0.4534 oz.

Step-by-step explanation:

Let us consider testing a hypothesis about a population mean with population standard deviation that is known,

Let the average body mass of the Goldfinch bird be μ^μ

Now our hypotheses are will be;

H₀ : μ = 0.5    and

H₁ : μ < 0.5

For the test, we shall use the z statistic which will be

z = (x"-μ)/(σ/√n)

Now given that;

σ = 0.04 and n = 4  

sample mean x" = ?

Now in order to be able to reject the null hypothesis, the p-value should be ≤ α = 0.01.

so to find the largest value of sample mean, we will use the maximum of p-value that is 0.01.

For a p-value = 0.01 at the lower tail (which is the percentile for z),

the corresponding z will be -2.33

so we substitute our values into our formula

z = (x"-μ)/(σ/√n)

z(σ/√n) = (x"-μ)

-2.33(0.04/√n) = (x"-0.5)

-0.0466 = x" - 0.5

x" = 0.5 - 0.0466

x"= 0.4534

therefore the largest value of the sample mean that will enable the experimenter to reject the null hypothesis is 0.4534 oz.

4 0
3 years ago
Write the ratio as a fraction in simplest form. 32:42
maks197457 [2]
16/21 is your answer

You can take a 2 out of both numbers to get your answer

I hope this helped! :)

3 0
3 years ago
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Can someone help me with this question please?
WITCHER [35]

Answer:

3

Step-by-step explanation:

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2 years ago
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Considering a bag of marbles has 5 green marbles, 3 blue marbles, and 2 red marbles. Three marbles are drawn in sequence and are
kipiarov [429]

Answer:

A

Step-by-step explanation:

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6 0
3 years ago
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