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Pepsi [2]
3 years ago
9

G(x)=2x^2+3x+6 find g(p+3)

Mathematics
1 answer:
hichkok12 [17]3 years ago
5 0
We're finding the function of (p+3), which means wherever there's an x, we're replacing it with (p+3).
2 (p+3)^2 + 3 (p+3) + 6
Foil out (p+3)^2.
2 (p^2 + 6p + 9) + 3 (p+3) + 6
Distribute.
2p^2 + 12p + 18 + 3p + 9 + 6
Add like terms.
g (p+3) = 2p^2 + 15p + 33
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The volume of a box 4 in.wide,2 in.high and 5 in long is
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Answer:

im gonna say 40 in

Step-by-step explanation:

8 0
3 years ago
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What is the area of this triangle?
amid [387]
We can solve for the 3 triangle sides.
The left side is easy 6.
Second side² = 7² + 4²
Second side² = 49 + 16
Second side = square root (65)
Second side = <span> <span> <span> 8.0622577483 </span> </span> </span>
Third Side² = 7² + 2²
Third Side² = 53
Third Side = <span> <span> <span> 7.2801098893 </span> </span> </span>
When we know 3 sides, we use Heron's formula for calculating area:
Perimeter = <span> <span> <span> 21.3423676376 </span> </span> </span>
Semi-Perimeter = <span> <span> <span> 10.6711838188 </span> </span> </span>
Using Heron's Formula
area = square root (<span>10.6711838188 * </span><span>4.6711838188 * </span> <span> <span> <span> 2.6089260705 </span> </span> </span> * <span> <span> <span> 3.3910739295 </span> </span> </span> )
area = square root (441)
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Yes, it's just that "easy".  LOL

7 0
4 years ago
Find the measure of each exterior angle of a regular 56-gon. Round to the nearest tenth.
Allisa [31]

Answer: The measure of each exterior angle is 6.4°.

Step-by-step explanation:

Since we have given that

Number of sides = 56

We have to find the measure of each exterior angles:

As we know the formula :

\text{ measure of each exterior angle}=\frac{360^\cir}{\text{Number of sides}}\\\\\text{ measure of each exterior angle}=\frac{360}{56}\\\\\text{ measure of each exterior angle}=6.4^\circ

Hence, the measure of each exterior angle is 6.4°.

6 0
3 years ago
How to pick a good number while dealing with equivalent fraction s
klemol [59]
I don't know what you mean but when you want to find equivalent fractions, I would use 10.
Ex: 6/9=60/90
7 0
3 years ago
Read 2 more answers
Ecuación de la hipérbola con centro en (0;0), focos en abrir paréntesis 0 coma espacio menos raíz cuadrada de 28 cerrar paréntes
yaroslaw [1]

Answer:

\frac{y^{2}}{25}-\frac{x^{2}}{3}=1

Step-by-step explanation:

Para resolver este problema debemos tomar en cuenta los datos que nos dan y la ecuación de una hipérbola. Comencemos con los datos:

centro: (0,0)

focos: (0,-\sqrt{28}),(0,\sqrt{28})

eje conjugado = 2\sqrt{3}

por los focos podemos ver que la hipérbola se dirige hacia el eje y, por lo que debemos tomar la siguiente forma de la ecuación de la parábola:

\frac{y^{2}}{a^{2}}+\frac{x^{2}}{b^{2}}=1

de los focos podemos obtener que:

c=\sqrt{28}

y del eje conjugado podemos saber que al dividir la longitud del eje conjugado dentro de 2 obtenemos b, así que:

b=\sqrt{3}

podemos utilizar la siguiente fórmula para obtener a:

c^{2}-a^{2}=b^{2}

si despejamos a en la ecuación obtenemos lo siguiente:

a=\sqrt{c^{2}-b^{2}}

ahora podemos sustituir los valores:

a=\sqrt{(\sqrt{28})^{2}-(\sqrt{3})^{2}}

a=\sqrt{28-3}

a=\sqrt{25}

a=5

así que media vez conozcamos a, podemos sustituir los datos en la ecuación de la hipérbola así que obtenemos lo siguiente:

\frac{y^{2}}{a^{2}}+\frac{x^{2}}{b^{2}}=1

\frac{y^{2}}{(5)^{2}}+\frac{x^{2}}{(\sqrt{3})^{2}}=1

\frac{y^{2}}{25}+\frac{x^{2}}{3}=1

si graficamos la hipérbola, queda como en el documento adjunto.

7 0
3 years ago
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