Answer:
The solution is (-2,2)
Step-by-step explanation:
The graph is shown below.
Answer:
A.-
D.
E.
Step-by-step explanation:
Like terms must have the same variable, in this case x, and the same exponent, in this case 2. Since the original term is
, the like terms will be those that contain
, regardless of whether their coefficient or sign is different.
Analyzing the options:
A.-
We have the same variable and the same exponent
, so it is a like term.
B. 
You have the same variable x but not the same exponent. So it's not a like term of 
C.
Same variable
but as in the previous case, the exponent is different, it is a 3 and it should be a 2, so it is not a similar or like term.
D.
In this option we do have the
, so it is a like term of 
E.
It is also a like term because it contains the
.
In summary the like terms are:
A.-
D.
E.
It would be A, because I remember working on the same question
Answer: 
Step-by-step explanation:
Given
The ratio of the area of the similar triangles is equal to the square of the side of the corresponding sides
Suppose the corresponding side on figure A is 
On solving
![\Rightarrow \dfrac{16}{49}=[\dfrac{x}{5}]^2\\\\\Rightarrow \dfrac{x}{5}=\sqrt{\dfrac{16}{49}}\\\\\Rightarrow \dfrac{x}{5}=\dfrac{4}{7}\\\\\Rightarrow x=\dfrac{20}{7}](https://tex.z-dn.net/?f=%5CRightarrow%20%5Cdfrac%7B16%7D%7B49%7D%3D%5B%5Cdfrac%7Bx%7D%7B5%7D%5D%5E2%5C%5C%5C%5C%5CRightarrow%20%5Cdfrac%7Bx%7D%7B5%7D%3D%5Csqrt%7B%5Cdfrac%7B16%7D%7B49%7D%7D%5C%5C%5C%5C%5CRightarrow%20%5Cdfrac%7Bx%7D%7B5%7D%3D%5Cdfrac%7B4%7D%7B7%7D%5C%5C%5C%5C%5CRightarrow%20x%3D%5Cdfrac%7B20%7D%7B7%7D)