Volume of a cone, V = πr^2h/3
r = Sqrt 3V/πh = Sqrt [(58.9*3)/(3.14*9)] = 2.5 cm, minimum
Surface area, A = πr [r+ Sqrt (h^2+r^2)] = 3.14*2.5*[2.5+ Sqrt (9^2+2.5^2)] = 92.95 cm^2
Therefore, minimum amount of paper required is 92.95 cm^2
Answer:
Step-by-step explanation:
If the new height is 338m and the helicopter decended 127m to get to that new height then the original height is simply the sum of them both.
H = 338m + 127m
H = 465m
12x - 8y = -12
6x + 4y = -30
Multiply the 2nd equation by 2, to make the Y coefficients opposite:
6x + 4y = -30 x 2 = 12x + 8y = -60
Now add the two equations:
12x -8y = -12 + 12x +8y = -60
= 24x = -72
Divide bothe sides by 24 to solve for x:
x = -72/24
x = -3
Now replace x with -3 in the first equation to solve for y:
12(-3) - 8y = -12
-36 - 8y = -12
Add 36 to each side:
-8y = 24
Divide both sides by -8 to solve for y:
y = 24 / -8
y = -3
X = -3 and y = -3
(-3,-3)
Answer:
The answer is A hope it helps!
