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3 years ago

Given the term 3x², select ALL of the like terms listed below. Question 3 options: A.-2x²

Mathematics

1 answer:

atroni [7]3 years ago

7 0

Answer:

A.- $2x^2$

D. $5x^2$

E. $x^2$

Step-by-step explanation:

Like terms must have the same variable, in this case x, and the same exponent, in this case 2. Since the original term is $3x^2$ , the like terms will be those that contain $x^2$ , regardless of whether their coefficient or sign is different.

Analyzing the options:

A.- $2x^2$

We have the same variable and the same exponent $x^2$ , so it is a like term.

B. $3x$

You have the same variable x but not the same exponent. So it's not a like term of $3x^2$

C. $3x^3$

Same variable $x$ but as in the previous case, the exponent is different, it is a 3 and it should be a 2, so it is not a similar or like term.

D. $5x^2$

In this option we do have the $x^2$ , so it is a like term of $3x^2$

E. $x^2$

It is also a like term because it contains the $x^2$ .

In summary the like terms are:

A.- $2x^2$

D. $5x^2$

E. $x^2$

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abruzzese [7]

Answer:

2/5

Step-by-step explanation:

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3 years ago

A hot tub has capacity of 1458 liters 487 liters and 750 ml were put in how much more needs to be put in

Colt1911 [192]

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3 years ago

Which number line shows the solution for

Brums [2.3K]

Answer:

It's the last choice.

Step-by-step explanation:

| n | ≤ 2 represents the distance between n and 0 that is less than or equal to 2. The dots on the 2 and -2 are black because the equal sign is part of the inequality.

Note the vertical lines about the n mean the absolute value of n - the positive distance between n and 0, which has a maximum of 2 either side of the 0.

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3 years ago

0.145 as a fraction or a mixed number.

Vlad1618 [11]

we can convert any decimal to a fraction, by simply <u>using as many zeros at the bottom as there are decimals, and losing the dot atop</u>, now let's do so, notice we have 3 decimals, so we'll use 3 zeros.

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3 years ago

A car is being driven at a rate of 40 ft/sec when the brakes are applied. The car decelerates at a constant rate of 10 ft/sec2.

IRISSAK [1]

Answer:

80 feet

Step-by-step explanation:

Given:

Initial speed of the car ( $v_0$ ) = 40 ft/sec

Deceleration of the car ( $\frac{dv}{dt}$ ) = -10 ft/sec²

Final speed of the car ( $v_x$ ) = 0 ft/sec

Let the distance traveled by the car be 'x' at any time 't'. Let 'v' be the velocity at any time 't'.

Now, deceleration means rate of decrease of velocity.

So, $\frac{dv}{dt}=-10\ ft/sec^2$

Negative sign means the velocity is decreasing with time.

Now, $\frac{dv}{dt}=\frac{dv}{dx}(\frac{dx}{dt})$ using chain rule of differentiation. Therefore,

$\frac{dv}{dx}\cdot\frac{dx}{dt}= -10\\\\But\ \frac{dx}{dt}=v.\ So,\\\\v\frac{dv}{dx}=-10\\\\vdv=-10dx$

Integrating both sides under the limit 40 to 0 for 'v' and 0 to 'x' for 'x'. This gives,

$\int\limits^0_{40} {v} \, dv=\int\limits^x_0 {-10} \, dx\\\\\left [ \frac{v^2}{2} \right ]_{40}^{0}=-10x\\\\-10x=\frac{0}{2}-\frac{1600}{2}\\\\10x=800\\\\x=\frac{800}{10}=80\ ft$

Therefore, the car travels a distance of 80 feet before stopping.

4 0

3 years ago