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julsineya [31]
4 years ago
13

a survey is taken to determine which type of vehicle is shown most popular. the data is shown in the bar graph below. what can y

ou conclude about the survey?

Mathematics
1 answer:
matrenka [14]4 years ago
7 0
I believe it could be G or I(j?)
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Simplify by rationalizing the denominator.<br> 15√2 / √270
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\frac{ \sqrt{15} }{3} ✅

Step-by-step explanation:

\frac{15 \sqrt{2} }{ \sqrt{270} }  \\ \\ =  \frac{15 \sqrt{2} }{ \sqrt{270} }   \times  \frac{ \sqrt{270} }{ \sqrt{270} }  \\  \\=  \frac{15 \sqrt{2}  \times  \sqrt{270} }{270}  \\\\ (∵ \sqrt{a}  \times  \sqrt{a}  = a) \\\\  =  \frac{15 \sqrt{540} }{270}  \\  \\=  \frac{ \sqrt{2 \times 2 \times 3 \times 3 \times 3 \times 5} }{18}  \\ \\ =  \frac{ \sqrt{ {2}^{2} \times  {3}^{2}  \times 15 } }{18}  \\  =  \frac{2 \times 3 \sqrt{15} }{18}  \\ \\ =  \frac{6 \sqrt{15} }{18}  \\ \\ =  \frac{ \sqrt{15} }{3}

\large\mathfrak{{\pmb{\underline{\orange{Mystique35 }}{\orange{♡}}}}}

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3 years ago
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Having the information on how many events there are and how many people in each event there would help me personally solve this

what i can tell you is its a probability thing a tree diagram is starting with something, like flipping a coin, and creating a branch for heads and tails, 0.5 for each branch. like the attachment I have on here. there's only 2 probable results from a coin, but if I have 5 events with 50 competitors I've created a lot more probable outcomes, it also depends on the events, if one of my competitors in 6'9" and ones 5'2" and the event is a dunk contest it would be slightly unfair and the probability of the person who is 5'2" changing your tree diagram :)

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2 years ago
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