F(1)=3f(1)=3 and f(n)=2f(n-1)+3 f(n)=2f(n−1)+3 then find the value of f(3)

Mathematics

1 answer:

gayaneshka [121]2 years ago

7 0

Answer:

f(3)=21

Step-by-step explanation:

f(1)=3

f(n)=2f(n-1)+3

n=2

f(2)=2f(2-1)+3

f(2)=2f(1)+3

f(2)=2*3+3

f(2)=6+3

f(2)=9

n=3

f(3)=2f(3-1)+3

f(3)=2f(2)+3

f(3)=2*9+3

f(3)=18+3

f(3)=21

You might be interested in

Find the unit vector in the direction of u = (-3,2).

DENIUS [597]

$\bf \textit{unit vector for }(a,b)\implies \left( \cfrac{a}{\sqrt{a^2+b^2}}~~,~~\cfrac{b}{\sqrt{a^2+b^2}} \right)\\\\
-------------------------------\\\\
(-3,2)\qquad \stackrel{unit~vector}{\implies }\qquad \left( \cfrac{-3}{\sqrt{(-3)^2+2^2}}~~,~~\cfrac{2}{\sqrt{(-3)^2+2^2}} \right)
\\\\\\
\left( -\cfrac{3}{\sqrt{13}}~~,~~ \cfrac{2}{\sqrt{13}}\right)\\\\
-------------------------------$

$\bf \textit{and now let's \underline{rationalize} the denominator for each}
\\\\\\
-\cfrac{3}{\sqrt{13}}\cdot \cfrac{\sqrt{13}}{\sqrt{13}}\implies -\cfrac{3\sqrt{13}}{13} \qquad \qquad \qquad \qquad \cfrac{2}{\sqrt{13}}\cdot \cfrac{\sqrt{13}}{\sqrt{13}}\implies \cfrac{2\sqrt{13}}{13}
\\\\\\
\textit{and written in \underline{ai+bj form}}\qquad -\cfrac{3\sqrt{13}}{13}i~~~~+~~~~\cfrac{2\sqrt{13}}{13}j$

7 0

2 years ago

HELP!!

Step2247 [10]

That’s easy it’s 200$

8 0

2 years ago

Amber has 5/2 pounds of salt dough for a project. she writes this equation to show 5/2. 5/2= 5×1/2

Alona [7]

If you would like to know whether or not what she wrote is accurate, it is.

Hope that helps!

3 0

3 years ago