F(1)=3f(1)=3 and f(n)=2f(n-1)+3
f(n)=2f(n−1)+3
then find the value of f(3)
1 answer:
Answer:
f(3)=21
Step-by-step explanation:
f(1)=3
f(n)=2f(n-1)+3
n=2
f(2)=2f(2-1)+3
f(2)=2f(1)+3
f(2)=2*3+3
f(2)=6+3
f(2)=9
n=3
f(3)=2f(3-1)+3
f(3)=2f(2)+3
f(3)=2*9+3
f(3)=18+3
f(3)=21
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