All categories

3 years ago

PLEASE HELP THANK YOU

Mathematics

2 answers:

Zanzabum3 years ago

8 0

Answer:

13- $2

15-52

Step-by-step explanation:

frutty [35]3 years ago

6 0

Answer:

13) A, $2

14) ?????

15) D, 52

16) ????

Step-by-step explanation:

13) 20 - 6 = 14. 14/7 = 2

14) SORRY I DON'T KNOW THE ANSWER

15) 300 - 196 = 104. 104/2 = 52

16) iDk tHe aNsWeR aGaIn- i rEaLly sUck aT tHeSe aLloWaNce qUeStIoNs

You might be interested in

Makikisagot po..thank you

Lilit [14]

I am confused whattt

3 0

3 years ago

Which scatterplot does NOT suggest a linear relationship between x and y?

Misha Larkins [42]

Ll only

because a linear relationship is like a straight line going up or down (but not horizontal)

6 0

3 years ago

Read 2 more answers

(cos x - (sqrt 2)/2)(sec x -1)=0

Darya [45]

$(\cos x-\frac{\sqrt{2}}{2})(\sec x-1)$ =0 [/tex]

$=(\cos x-\frac{1}{\sqrt{2}})(\sec x-1)$ =0 [/tex]

$\frac{(\sqrt{2}\cos x-1)}{\sqrt{2}}(\frac{1}{\cos x\ }-1)=0$

(Reciprocal Identity)

$(\frac{^{\sqrt{2}\\cos x-1}}{^{\sqrt{2}}})(\frac{1-\cos x}{\cos x})=0$

$\frac{^{(\sqrt{2}\cos x-1})}{\sqrt{2}}\frac{(1-\cos x)}{\cos x}=0$

$(\sqrt{2}\cos x-1}){(1-\cos x)}=0$ (ZeroProduct Property)

$\sqrt{2}\cos x-1=0$

$\sqrt{2}\cos x=1$

$\cos x=\frac{1}{\sqrt{2}}$

$x=\frac{\Pi }{4}$

and

$1-\cos x=0$

$\cos x=1$

$x=0$

x=0 and x= $\frac{\Pi }{4}$ are the solutions.

6 0

3 years ago

Read 2 more answers

A/9- -4 = ?<br><br> PLEASE HELP!!

Ganezh [65]

Answer:

$9 - ( - 4) \\ 9 + 4 = 13$

Step-by-step explanation:

negative + negative is positive

5 0

3 years ago

Simplifying rational expressions

Sonbull [250]

1. $\frac{(c + 8)(c - 8)}{(c - 8)(c + 3)}_,_$
   $\frac{c + 8}{c + 3}_,_$

2. $\frac{n^{2} + 4n - 12}{n^{2} + 2n - 8}_,_$
   $\frac{n^{2} + 6n - 2n - 12}{n^{2} + 4n - 2n - 8}_,_$
   $\frac{n(n) + n(6) - 2(n) - 2(6)}{n(n) + n(4) - 2(n) - 2(4)}_,_$
   $\frac{n(n + 6) - 2(n + 6)}{n(n + 4) - 2(n + 4)}_,_$
   $\frac{(n - 2)(n + 6)}{(n - 2)(n + 4)}_,_$
   $\frac{n + 6}{n + 4}_,_$

3. $\frac{42x^{2}y^{3}}{28x^{3}y}_,_$
   $\frac{3y^{2}}{2x}_,_$

4. $\frac{m^{2} - 3m - 10}{m - 5}_,_$
   $\frac{m^{2} - 5m + 2m - 10}{m - 5}_,_$
   $\frac{m(m) - m(5) + 2(m) - 2(5)}{m - 5}_,_$
   $\frac{m(m - 5) + 2(m - 5)}{m - 5}_,_$
   $\frac{(m + 2)(m - 5)}{m - 5}_,_$
   $m + 2_,_$

3 0

3 years ago