Answer:
b
Step-by-step explanation:
Using the trigonometric identities
cot x = and tan x =
thus
+ tanΘ × cosΘ
= +
× cosΘ
= cosΘ × + sinΘ
= sinΘ + sinΘ
= 2sinΘ → b
find the area of field in a form of trapezium whose parallel sides are 10 and 12 and perpendicular distance between them is 6 me
1 answer:
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Answer:
The diagonal is 421.
Step-by-step explanation:
This is a difficult question. To find the diagonal, you need to find the base and the height of the square. After that, you need to make it a triangle, by using this equation; (A being area, B being base, and H being height) then find the length of the hypotenuse of the triangle, which I will do for you.
The B and H = 416. Plug it into the equation now;
Now that you have done that, we know that the area of our new triangle is 86,528.
The diagonal is:
Ok, so the question is based on geometric progression. Remember, the formula for calculating the nth-term of a geometric progression is: . The a in the expression stands for the 1st term of the sequence, and r is the common ratio of the elements of the sequence. Now let's take a look at the problem.
"A ping pong ball has a 75% rebound ration". We can infer that our common ratio, r, is 75% which is 0.75.
"When you drop it from a height of k feet...", this means the first height you drop it from, a.k.a, the first term.
Now going back to the expression, the nth-term = , we can substitute our common ration, 0.75 with r, and our 1st term, k, with a. This becomes:
. This becomes our expression.
a. The highest height achieved by the ball after six bounces. Our nth-term here is 6, so let's use our expression to find the 6th term.
b. The total distance travelled by the ball when it strikes the ground for the 12th time. This involves the use of the sum of elements in the geometric progression. The formula for that is , provided that r is less than 1, which it is in this case, since 0.75 is less than one. Our nth-term here is 12, so we substitute.