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andrey2020 [161]
3 years ago
12

Find the percent of each number. 0.9 of 1000 =

Mathematics
1 answer:
Serggg [28]3 years ago
3 0

Answer:

9

Step-by-step explanation:

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Find the radius of a circle with an area of 380 square inches. Round your answer to the nearest hundredth.​
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Area of a circle is defined as

Area of a circle is defined asA = πr²

Area of a circle is defined asA = πr²Where

Area of a circle is defined asA = πr²WhereA is the area of the circle

Area of a circle is defined asA = πr²WhereA is the area of the circler Is the radius of the circle

Area of a circle is defined asA = πr²WhereA is the area of the circler Is the radius of the circleπ is a constant = 3.142

Area of a circle is defined asA = πr²WhereA is the area of the circler Is the radius of the circleπ is a constant = 3.142Then,

Area of a circle is defined asA = πr²WhereA is the area of the circler Is the radius of the circleπ is a constant = 3.142Then,Given that the area is 380 in²

Area of a circle is defined asA = πr²WhereA is the area of the circler Is the radius of the circleπ is a constant = 3.142Then,Given that the area is 380 in²So,

Area of a circle is defined asA = πr²WhereA is the area of the circler Is the radius of the circleπ is a constant = 3.142Then,Given that the area is 380 in²So,A = πr²

Area of a circle is defined asA = πr²WhereA is the area of the circler Is the radius of the circleπ is a constant = 3.142Then,Given that the area is 380 in²So,A = πr²380 = 3.142 × r²

Area of a circle is defined asA = πr²WhereA is the area of the circler Is the radius of the circleπ is a constant = 3.142Then,Given that the area is 380 in²So,A = πr²380 = 3.142 × r²Divide both side by 3.142

Area of a circle is defined asA = πr²WhereA is the area of the circler Is the radius of the circleπ is a constant = 3.142Then,Given that the area is 380 in²So,A = πr²380 = 3.142 × r²Divide both side by 3.142380 / 3.142 = 3.142 × r² / 3.142

Area of a circle is defined asA = πr²WhereA is the area of the circler Is the radius of the circleπ is a constant = 3.142Then,Given that the area is 380 in²So,A = πr²380 = 3.142 × r²Divide both side by 3.142380 / 3.142 = 3.142 × r² / 3.142111.372 = r²

Area of a circle is defined asA = πr²WhereA is the area of the circler Is the radius of the circleπ is a constant = 3.142Then,Given that the area is 380 in²So,A = πr²380 = 3.142 × r²Divide both side by 3.142380 / 3.142 = 3.142 × r² / 3.142111.372 = r²Take square root of both sides

Area of a circle is defined asA = πr²WhereA is the area of the circler Is the radius of the circleπ is a constant = 3.142Then,Given that the area is 380 in²So,A = πr²380 = 3.142 × r²Divide both side by 3.142380 / 3.142 = 3.142 × r² / 3.142111.372 = r²Take square root of both sides√111.372 = √r²

Area of a circle is defined asA = πr²WhereA is the area of the circler Is the radius of the circleπ is a constant = 3.142Then,Given that the area is 380 in²So,A = πr²380 = 3.142 × r²Divide both side by 3.142380 / 3.142 = 3.142 × r² / 3.142111.372 = r²Take square root of both sides√111.372 = √r²10.5533 = r

Area of a circle is defined asA = πr²WhereA is the area of the circler Is the radius of the circleπ is a constant = 3.142Then,Given that the area is 380 in²So,A = πr²380 = 3.142 × r²Divide both side by 3.142380 / 3.142 = 3.142 × r² / 3.142111.372 = r²Take square root of both sides√111.372 = √r²10.5533 = rr = 10.5533 in

Area of a circle is defined asA = πr²WhereA is the area of the circler Is the radius of the circleπ is a constant = 3.142Then,Given that the area is 380 in²So,A = πr²380 = 3.142 × r²Divide both side by 3.142380 / 3.142 = 3.142 × r² / 3.142111.372 = r²Take square root of both sides√111.372 = √r²10.5533 = rr = 10.5533 inNearest hundredth means to 2d.p

Area of a circle is defined asA = πr²WhereA is the area of the circler Is the radius of the circleπ is a constant = 3.142Then,Given that the area is 380 in²So,A = πr²380 = 3.142 × r²Divide both side by 3.142380 / 3.142 = 3.142 × r² / 3.142111.372 = r²Take square root of both sides√111.372 = √r²10.5533 = rr = 10.5533 inNearest hundredth means to 2d.pTherefore

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