Good morning Mr. William I wanted to ask you if it is still possible to change an elective class
Given:
In circle O, m∠R = 30.8°.
To find:
The m∠NOQ
Solution:
Central angle theorem: According to this theorem, the central angle is always twice of subtended angle on the same arc.
Angle NOQ and angle NRQ are on the same arc but ∠NOQ is the central angle and ∠NRQ is the subtended angle on the arc NQ.
Using central angle theorem, we get




Therefore,
.
Answer:
initial velocity = 64 m/s
Step-by-step explanation:
Differentiate H = 64t - 16t² to find an equation for velocity:
Velocity =
= 64 - 32t
Initial velocity (u) is when t = 0:
u = 64 - 32(0)
⇒ u = 64 - 0
⇒ u = 64 m/s
Answer:
(-4, -3), (4, -1), (8, 0), (12, 1)
Step-by-step explanation:
The x- and corresponding y-values are listed in the table. Put each pair in parentheses, <em>x-value first</em>. (That is an <em>ordered pair</em>.)
(x, y) = (-4, -3) . . . . from the first table entry
(x, y) = (4, -1) . . . . from the second table entry
(x, y) = (8, 0) . . . . from the third table entry
(x, y) = (12, 1) . . . . from the last table entry
Answer:
it is what it is take a guess
Step-by-step explanation: