Answer:// Solve equation [1] for the variable y
[1] y = 2x - 3
// Plug this in for variable y in equation [2]
[2] -2•(2x-3) + 2x = 2
[2] - 2x = -4
// Solve equation [2] for the variable x
[2] 2x = 4
[2] x = 2
// By now we know this much :// Solve equation [1] for the variable y
[1] y = 2x - 3
// Plug this in for variable y in equation [2]
[2] -2•(2x-3) + 2x = 2
[2] - 2x = -4
// Solve equation [2] for the variable x
[2] 2x = 4
[2] x = 2
// By now we know this much :
y = 2x-3
x = 2
// Use the x value to solve for y
y = 2(2)-3 = 1
y = 2x-3
x = 2
// Use the x value to solve for y
y = 2(2)-3 = 1
Step-by-step explanation:
Answer: for one you need to send the recipe and mark me as brainliest answer plz
Step-by-step explanation:
Answer:
x=17
y=10
Step-by-step explanation:
hope this helps you
The equation for this problem would be:
x+y = 16
Rearranging the equation, it can be expressed as:
y = 16 - x
To obtain ordered pairs, replace random values of x up to 16 to find the value of y. The ordered pairs are tabulated and the graph is shown in the attached picture.
We assume you want to find the inverse transform of s/(s^2 +3s -4). This can be written in partial fraction form as
(4/5)/(s+4) + (1/5)/(s-1)
which can be found in a table of transforms to be the transform of
(4/5)e^(-4t) + (1/5)e^t
_____
There are a number of ways to determine the partial fractions. They all start with factoring the denominator.
s^2 +3x -4 = (s+4)(s-1)
After that, you can postulate the final form and determine the values of the coefficients that make it so. For example:
A/(s+4) + B/(s-1) = ((A+B)s + (4B-A))/(s^2 +3x -4)
This gives rise to two equations:
(A+B) = 1
(4B-A) = 0
