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Oxana [17]
4 years ago
5

2 Points

Mathematics
1 answer:
ANTONII [103]4 years ago
6 0

Answer:

D

Step-by-step explanation:

This is called "implication". So if A (is true), then B MUST be true. If B is false, the implication is false. In all other cases, the implication is true. Suppose A is false, then it doesn't matter what B is, the implication is true, since we don't care what B is.

It's a bit confusing I suppose. Below is a truth table using P and Q in stead of A and B.

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If the hypotenuse of a right triangle measures 15 cm and one of the legs measures 12 cm, what is the length of the other leg?
Mama L [17]

Step-by-step explanation:

12 to the 2nd power=144

15 to the 2nd power =225

225-144=81

square root of 81 is 9

5 0
3 years ago
A 20-gallon container is filled halfway with a mixture that is $90\%$ vinegar and $10\%$ water. How many gallons of water must b
Yuki888 [10]

Answer:

5 gallons of water must be added.

10 gallons to start with

adding 'x' gallons of water      final volume = 10 + x

.9 (10) = amount of vinegar

.1(10) = amount of water

amount of vinegar before and after water addition is constant

.9(10) = .6(10+x)  

9 = 6 + .6x

3 = .6x

x = 5 gallons of water to be added

(i truly hope i helped you

8 0
2 years ago
What's the answer !!<br><br><img src="https://tex.z-dn.net/?f=%20%5Csqrt%7B58%20%5Ctimes%2058%7D%20" id="TexFormula1" title=" \s
Vladimir [108]

Solution given:

\sqrt{58 \times 58}

\sqrt{58²}=±58

8 0
3 years ago
Read 2 more answers
a semicircular flower bed has a diameter of 3m. What is the area of the flower bed. Give answer to one decimal place
MAVERICK [17]
You use the cricle fourmla (πr sqaure). and you will get 7.065
7 0
4 years ago
Which of the following functions gives the length of the base edge, a(v), of a right square pyramid that is 8 inches tall as a f
Reil [10]

Answer:

\large\boxed{a(V)=\sqrt{\dfrac{3V}{8}}}

Step-by-step explanation:

The formula of a volume of a square pyramid:

V=\dfrac{1}{3}a^2h

a - base edge

h - height of a pyramid

We have H = 8in.

Substitute and solve for a:

\dfrac{1}{3}a^2(8)=V\\\\\dfrac{8}{3}a^2=V\qquad\text{multiply both sides by}\ \dfrac{3}{8}\\\\\dfrac{3\!\!\!\!\diagup^1}{8\!\!\!\!\diagup_1}\cdot\dfrac{8\!\!\!\!\diagup^1}{3\!\!\!\!\diagup_1}a^2=\dfrac{3}{8}V\\\\a^2=\dfrac{3V}{8}\Rightarrow a=\sqrt{\dfrac{3V}{8}}

3 0
3 years ago
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